Questions — AQA Paper 2 (140 questions)

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AQA Paper 2 2021 June Q2
2 A curve has equation \(y = \mathrm { f } ( x )\) The curve has a point of inflection at \(x = 7\)
It is given that \(\mathrm { f } ^ { \prime } ( 7 ) = a\) and \(\mathrm { f } ^ { \prime \prime } ( 7 ) = b\), where \(a\) and \(b\) are real numbers. Identify which one of the statements below must be true.
Circle your answer.
\(\mathrm { f } ^ { \prime } ( 7 ) \neq 0\)
\(\mathrm { f } ^ { \prime } ( 7 ) = 0\)
\(\mathrm { f } ^ { \prime \prime } ( 7 ) \neq 0\)
\(\mathrm { f } ^ { \prime \prime } ( 7 ) = 0\)
AQA Paper 2 2021 June Q3
3 A sequence is defined by $$u _ { 1 } = a \text { and } u _ { n + 1 } = - 1 \times u _ { n }$$ Find \(\sum _ { n = 1 } ^ { 95 } u _ { n }\)
Circle your answer.
\(- a\)
0
\(a\)
95a
AQA Paper 2 2021 June Q4
4
  1. On Figure 1 add a sketch of the graph of $$y = | 3 x - 6 |$$ 4
  2. Find the coordinates of the points of intersection of the two graphs.
    Fully justify your answer.
    \includegraphics[max width=\textwidth, alt={}, center]{b7df05bf-f3fc-4705-a13c-6b562896fa9f-05_2488_1716_219_153}
AQA Paper 2 2021 June Q5
5 Express $$\frac { 5 ( x - 3 ) } { ( 2 x - 11 ) ( 4 - 3 x ) }$$ in the form $$\frac { A } { ( 2 x - 11 ) } + \frac { B } { ( 4 - 3 x ) }$$ where \(A\) and \(B\) are integers.
AQA Paper 2 2021 June Q6
6 Show that the solution of the equation $$5 ^ { x } = 3 ^ { x + 4 }$$ can be written as $$x = \frac { \ln 81 } { \ln 5 - \ln 3 }$$ Fully justify your answer.
AQA Paper 2 2021 June Q7
7 A circle has equation $$x ^ { 2 } + y ^ { 2 } - 6 x - 8 y = p$$ 7
    1. State the coordinates of the centre of the circle.
      7
  1. (ii) Find the radius of the circle in terms of \(p\).
    7
  2. The circle intersects the coordinate axes at exactly three points. Find the two possible values of \(p\).
AQA Paper 2 2021 June Q8
8 Kai is proving that \(n ^ { 3 } - n\) is a multiple of 3 for all positive integer values of \(n\). Kai begins a proof by exhaustion.
Step 1 $$n ^ { 3 } - n = n \left( n ^ { 2 } - 1 \right)$$ Step 2 When \(n = 3 m\), where \(m\) is a \(n ^ { 3 } - n = 3 m \left( 9 m ^ { 2 } - 1 \right)\) non-negative integer which is a multiple of 3 Step 3 When \(n = 3 m + 1\), $$\begin{aligned} & n ^ { 3 } - n = ( 3 m + 1 ) \left( ( 3 m + 1 ) ^ { 2 } - 1 \right)
& = ( 3 m + 1 ) \left( 9 m ^ { 2 } \right)
& = 3 ( 3 m + 1 ) \left( 3 m ^ { 2 } \right) \end{aligned}$$ Step 5 Therefore \(n ^ { 3 } - n\) is a multiple of 3 for all positive integer values of \(n\) 8
  1. Explain the two mistakes that Kai has made after Step 3. Step 4 \section*{which is a multiple of 3
    which is a multiple of 3}
    \includegraphics[max width=\textwidth, alt={}]{b7df05bf-f3fc-4705-a13c-6b562896fa9f-10_67_134_964_230}

    all positive integer values of \(n\) \section*{a} \includegraphics[max width=\textwidth, alt={}]{b7df05bf-f3fc-4705-a13c-6b562896fa9f-10_58_49_1037_370} 墐 pount \(\_\_\_\_\)
    \(\_\_\_\_\) " \(\_\_\_\_\)
    8
  2. Correct Kai's argument from Step 4 onwards.
AQA Paper 2 2021 June Q9
9 A robotic arm which is attached to a flat surface at the origin \(O\), is used to draw a graphic design. The arm is made from two rods \(O P\) and \(P Q\), each of length \(d\), which are joined at \(P\).
A pen is attached to the arm at \(Q\).
The coordinates of the pen are controlled by adjusting the angle \(O P Q\) and the angle \(\theta\) between \(O P\) and the \(x\)-axis. For this particular design the pen is made to move so that the two angles are always equal to each other with \(0 \leq \theta \leq \frac { \pi } { 2 }\) as shown in Figure 2. \begin{figure}[h]
\captionsetup{labelformat=empty} \caption{Figure 2} \includegraphics[alt={},max width=\textwidth]{b7df05bf-f3fc-4705-a13c-6b562896fa9f-12_805_867_989_584}
\end{figure} 9
  1. Show that the \(x\)-coordinate of the pen can be modelled by the equation $$x = d \left( \cos \theta + \sin \left( 2 \theta - \frac { \pi } { 2 } \right) \right)$$ 9
  2. Hence, show that $$x = d \left( 1 + \cos \theta - 2 \cos ^ { 2 } \theta \right)$$ 9
  3. It can be shown that $$x = \frac { 9 d } { 8 } - d \left( \cos \theta - \frac { 1 } { 4 } \right) ^ { 2 }$$ State the greatest possible value of \(x\) and the corresponding value of \(\cos \theta\)
    9
  4. Figure 3 below shows the arm when the \(x\)-coordinate is at its greatest possible value. \begin{figure}[h]
    \captionsetup{labelformat=empty} \caption{Figure 3} \includegraphics[alt={},max width=\textwidth]{b7df05bf-f3fc-4705-a13c-6b562896fa9f-14_570_773_456_630}
    \end{figure} Find, in terms of \(d\), the exact distance \(O Q\).
    \includegraphics[max width=\textwidth, alt={}, center]{b7df05bf-f3fc-4705-a13c-6b562896fa9f-15_2488_1716_219_153}
AQA Paper 2 2021 June Q10
8 marks
10 The function h is defined by $$\mathrm { h } ( x ) = \frac { \sqrt { x } } { x - 3 }$$ where \(h\) has its maximum possible domain.
10
  1. Find the domain of h .
    Give your answer using set notation. 10
  2. Alice correctly calculates $$h ( 1 ) = - 0.5 \text { and } h ( 4 ) = 2$$ She then argues that since there is a change of sign there must be a value of \(x\) in the interval \(1 < x < 4\) that gives \(\mathrm { h } ( x ) = 0\) Explain the error in Alice's argument.
    [0pt] [2 marks]
    10
  3. By considering any turning points of h , determine whether h has an inverse function. Fully justify your answer.
    [0pt] [6 marks]
AQA Paper 2 2021 June Q11
11 A particle's displacement, \(r\) metres, with respect to time, \(t\) seconds, is defined by the equation $$r = 3 \mathrm { e } ^ { 0.5 t }$$ Find an expression for the velocity, \(v \mathrm {~m} \mathrm {~s} ^ { - 1 }\), of the particle at time \(t\) seconds.
Circle your answer.
\(v = 1.5 \mathrm { e } ^ { 0.5 t }\)
\(v = 6 \mathrm { e } ^ { 0.5 t }\)
\(v = 1.5 t \mathrm { e } ^ { 0.5 t }\)
\(v = 6 t e ^ { 0.5 t }\)
AQA Paper 2 2021 June Q12
1 marks
12 A particle has a speed of \(6 \mathrm {~ms} ^ { - 1 }\) in a direction relative to unit vectors \(\mathbf { i }\) and \(\mathbf { j }\) as shown in the diagram below.
\includegraphics[max width=\textwidth, alt={}, center]{b7df05bf-f3fc-4705-a13c-6b562896fa9f-18_307_542_1528_749} The velocity of this particle can be expressed as a vector \(\left[ \begin{array} { l } v _ { 1 }
v _ { 2 } \end{array} \right] \mathrm { ms } ^ { - 1 }\)
Find the correct expression for \(v _ { 2 }\)
Circle your answer.
[0pt] [1 mark]
\(v _ { 2 } = 6 \cos 30 ^ { \circ }\)
\(v _ { 2 } = 6 \sin 30 ^ { \circ }\)
\(v _ { 2 } = - 6 \sin 30 ^ { \circ }\)
\(v _ { 2 } = - 6 \cos 30 ^ { \circ }\)
AQA Paper 2 2021 June Q13
13 A vehicle, of total mass 1200 kg , is travelling along a straight, horizontal road at a constant speed of \(13 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) This vehicle begins to accelerate at a constant rate.
After 40 metres it reaches a speed of \(17 \mathrm {~ms} ^ { - 1 }\)
Find the resultant force acting on the vehicle during the period of acceleration.
AQA Paper 2 2021 June Q14
14 A motorised scooter is travelling along a straight path with velocity \(v \mathrm {~m} \mathrm {~s} ^ { - 1 }\) over time \(t\) seconds as shown by the following graph.
\includegraphics[max width=\textwidth, alt={}, center]{b7df05bf-f3fc-4705-a13c-6b562896fa9f-20_1120_1134_420_452} Noosha says that, in the period \(\mathbf { 1 2 } \leq \boldsymbol { t } \leq \mathbf { 3 6 }\), the scooter travels approximately 130 metres. Determine if Noosha is correct, showing clearly any calculations you have used.
AQA Paper 2 2021 June Q15
15 A cyclist is towing a trailer behind her bicycle. She is riding along a straight, horizontal path at a constant speed.
\includegraphics[max width=\textwidth, alt={}, center]{b7df05bf-f3fc-4705-a13c-6b562896fa9f-22_371_723_447_657} A tension of \(T\) newtons acts on the connecting rod between the bicycle and the trailer.
The cyclist is causing a constant driving force of 40 N to be applied whilst pedalling forwards on her bicycle. The constant resistance force acting on the trailer is 12 N
15
  1. State the value of \(T\) giving a clear reason for your answer.
    15
  2. State one assumption you have made in reaching your answer to part (a).
AQA Paper 2 2021 June Q16
16 A straight uniform rod, \(A B\), has length 6 m and mass 0.2 kg A particle of weight \(w\) newtons is fixed at \(A\).
A second particle of weight \(3 w\) newtons is fixed at \(B\).
The rod is suspended by a string from a point \(x\) metres from \(B\).
The rod rests in equilibrium with \(A B\) horizontal and the string hanging vertically as shown in the diagram below.
\includegraphics[max width=\textwidth, alt={}, center]{b7df05bf-f3fc-4705-a13c-6b562896fa9f-24_410_1148_767_445} Show that $$x = \frac { 3 w + 0.3 g } { 2 w + 0.1 g }$$ \includegraphics[max width=\textwidth, alt={}, center]{b7df05bf-f3fc-4705-a13c-6b562896fa9f-25_2488_1716_219_153}
AQA Paper 2 2021 June Q17
17 A ball is released from a great height so that it falls vertically downwards towards the surface of the Earth. 17
  1. Using a simple model, Andy predicts that the velocity of the ball, exactly 2 seconds after being released from rest, is \(2 g \mathrm {~m} \mathrm {~s} ^ { - 1 }\) Show how Andy has obtained his prediction.
    17
  2. Using a refined model, Amy predicts that the ball's acceleration, \(a \mathrm {~ms} ^ { - 2 }\), at time \(t\) seconds after being released from rest is $$a = g - 0.1 v$$ where \(v \mathrm {~m} \mathrm {~s} ^ { - 1 }\) is the velocity of the ball at time \(t\) seconds. Find an expression for \(v\) in terms of \(t\).
    17
  3. Comment on the value of \(v\) for the two models as \(t\) becomes large.
AQA Paper 2 2021 June Q18
2 marks
18 Two particles, \(P\) and \(Q\), are projected at the same time from a fixed point \(X\), on the ground, so that they travel in the same vertical plane.
\(P\) is projected at an acute angle \(\theta ^ { \circ }\) to the horizontal, with speed \(u \mathrm {~ms} ^ { - 1 }\)
\(Q\) is projected at an acute angle \(2 \theta ^ { \circ }\) to the horizontal, with speed \(2 u \mathrm {~m} \mathrm {~s} ^ { - 1 }\)
Both particles land back on the ground at exactly the same point, \(Y\).
Resistance forces to motion may be ignored.
18
  1. Show that $$\cos 2 \theta = \frac { 1 } { 8 }$$ 18
  2. \(\quad P\) takes a total of 0.4 seconds to travel from \(X\) to \(Y\).
    Find the time taken by \(Q\) to travel from \(X\) to \(Y\).
    18
  3. State one modelling assumption you have chosen to make in this question.
    [0pt] [1 mark]
    \begin{center} \begin{tabular}{|l|l|} \hline 19 & \begin{tabular}{l} Two skaters, Jo and Amba, are separately skating across a smooth, horizontal surface of ice.
    Both are moving in the same direction, so that their paths are straight and are parallel to each other.
    Jo is moving with constant velocity \(( 2.8 \mathbf { i } + 9.6 \mathbf { j } ) \mathrm { m } \mathrm { s } ^ { - 1 }\)
    At time \(t = 0\) seconds Amba is at position ( \(2 \mathbf { i } - 7 \mathbf { j }\) ) metres and is moving with a constant speed of \(8 \mathrm {~m} \mathrm {~s} ^ { - 1 }\)
    Explain why Amba's velocity must be in the form \(k ( 2.8 \mathbf { i } + 9.6 \mathbf { j } ) \mathrm { m } \mathrm { s } ^ { - 1 }\), where \(k\) is a constant.
    [0pt] [1 mark] \(\_\_\_\_\) \(\_\_\_\_\) \(\_\_\_\_\)
AQA Paper 2 2021 June Q19
4 marks
19
  1. (ii) Verify that \(k = 0.8\)
    [0pt] [1 mark] \(\_\_\_\_\) \(\_\_\_\_\) \(\_\_\_\_\)
    19
  2. Find the position vector of Amba when \(t = 4\)
    [0pt] [3 marks] \(\_\_\_\_\) \(\_\_\_\_\) \(\_\_\_\_\) \(\_\_\_\_\) \(\_\_\_\_\) \(\_\_\_\_\) \(\_\_\_\_\) \(\_\_\_\_\) \(\_\_\_\_\)
    \end{tabular}
    \hline \end{tabular} \end{center} 19
  3. At both \(t = 0\) and \(t = 4\) there is a distance of 5 metres between Jo and Amba's positions. Determine the shortest distance between their two parallel lines of motion.
    Fully justify your answer.
    \includegraphics[max width=\textwidth, alt={}, center]{b7df05bf-f3fc-4705-a13c-6b562896fa9f-32_2492_1721_217_150}
AQA Paper 2 2022 June Q1
1 A circle has centre \(( 4 , - 5 )\) and radius 6
Find the equation of the circle.
Tick ( \(\checkmark\) ) one box. $$\begin{aligned} & ( x - 4 ) ^ { 2 } + ( y + 5 ) ^ { 2 } = 6
& ( x + 4 ) ^ { 2 } + ( y - 5 ) ^ { 2 } = 6
& ( x - 4 ) ^ { 2 } + ( y + 5 ) ^ { 2 } = 36
& ( x + 4 ) ^ { 2 } + ( y - 5 ) ^ { 2 } = 36 \end{aligned}$$ □



AQA Paper 2 2022 June Q2
2 State the value of $$\lim _ { h \rightarrow 0 } \frac { \sin ( \pi + h ) - \sin \pi } { h }$$ Circle your answer.
\(\cos h\)
-1
0
1
AQA Paper 2 2022 June Q3
3 The function f is concave and is represented by one of the graphs below. Identify the graph which represents f . Tick ( \(\checkmark\) ) one box.
\includegraphics[max width=\textwidth, alt={}, center]{ad6590e8-6673-45ca-bef3-a14716978827-03_709_561_632_191}
\includegraphics[max width=\textwidth, alt={}, center]{ad6590e8-6673-45ca-bef3-a14716978827-03_117_111_927_826}
\includegraphics[max width=\textwidth, alt={}, center]{ad6590e8-6673-45ca-bef3-a14716978827-03_716_570_630_1082} □
\includegraphics[max width=\textwidth, alt={}, center]{ad6590e8-6673-45ca-bef3-a14716978827-03_711_563_1503_191}
\includegraphics[max width=\textwidth, alt={}, center]{ad6590e8-6673-45ca-bef3-a14716978827-03_711_565_1503_1085}
\includegraphics[max width=\textwidth, alt={}, center]{ad6590e8-6673-45ca-bef3-a14716978827-03_117_113_1800_1717}
AQA Paper 2 2022 June Q4
4 The diagram shows a triangle \(A B C\).
\(A B\) is the shortest side. The lengths of \(A C\) and \(B C\) are 6.1 cm and 8.7 cm respectively. The size of angle \(A B C\) is \(38 ^ { \circ }\)
Find the size of the largest angle.
Give your answer to the nearest degree.
\includegraphics[max width=\textwidth, alt={}, center]{ad6590e8-6673-45ca-bef3-a14716978827-05_2488_1716_219_153}
AQA Paper 2 2022 June Q5
2 marks
5 The binomial expansion of \(( 2 + 5 x ) ^ { 4 }\) is given by $$( 2 + 5 x ) ^ { 4 } = A + 160 x + B x ^ { 2 } + 1000 x ^ { 3 } + 625 x ^ { 4 }$$ 5
  1. Find the value of \(A\) and the value of \(B\).
    [0pt] [2 marks]
    L
    5
  2. Show that $$( 2 + 5 x ) ^ { 4 } - ( 2 - 5 x ) ^ { 4 } = C x + D x ^ { 3 }$$ where \(C\) and \(D\) are constants to be found.
    5
  3. Hence, or otherwise, find $$\int \left( ( 2 + 5 x ) ^ { 4 } - ( 2 - 5 x ) ^ { 4 } \right) \mathrm { d } x$$
AQA Paper 2 2022 June Q6
1 marks
6
  1. Asif notices that \(24 ^ { 2 } = 576\) and \(2 + 4 = 6\) gives the last digit of 576 He checks two more examples: $$\begin{array} { l c } 27 ^ { 2 } = 729 & 29 ^ { 2 } = 841
    2 + 7 = 9 & 2 + 9 = 11
    \text { Last digit } 9 & \text { Last digit } 1 \end{array}$$ Asif concludes that he can find the last digit of any square number greater than 100 by adding the digits of the number being squared. Give a counter example to show that Asif's conclusion is not correct. 6
  2. Claire tells Asif that he should look only at the last digit of the number being squared. $$\begin{array} { c c } 27 ^ { 2 } = 729 & 24 ^ { 2 } = 576
    7 ^ { 2 } = 49 & 4 ^ { 2 } = 16
    \text { Last digit } 9 & \text { Last digit } 6 \end{array}$$ Using Claire's method determine the last digit of \(23456789 { } ^ { 2 }\)
    [0pt] [1 mark] 6
  3. Given Claire's method is correct, use proof by exhaustion to show that no square number has a last digit of 8
AQA Paper 2 2022 June Q7
7 The curve \(y = 15 - x ^ { 2 }\) and the isosceles triangle \(O P Q\) are shown on the diagram The curve \(y = 15 - x ^ { 2 }\) and the isosceles triangle \(O P Q\) are shown on the diagram below.
\includegraphics[max width=\textwidth, alt={}, center]{ad6590e8-6673-45ca-bef3-a14716978827-10_759_810_388_614} Vertices \(P\) and \(Q\) lie on the curve such that \(Q\) lies vertically above some point ( \(q , 0\) ) The line \(P Q\) is parallel to the \(x\)-axis. 7
  1. Show that the area, \(A\), of the triangle \(O P Q\) is given by $$A = 15 q - q ^ { 3 } \quad \text { for } 0 < q < c$$ where \(c\) is a constant to be found.
    7
  2. Find the exact maximum area of triangle \(O P Q\). Fully justify your answer.