AQA Paper 2 2021 June — Question 10 8 marks

Exam BoardAQA
ModulePaper 2 (Paper 2)
Year2021
SessionJune
Marks8
TopicComposite & Inverse Functions

10 The function h is defined by $$\mathrm { h } ( x ) = \frac { \sqrt { x } } { x - 3 }$$ where \(h\) has its maximum possible domain.
10
  1. Find the domain of h .
    Give your answer using set notation. 10
  2. Alice correctly calculates $$h ( 1 ) = - 0.5 \text { and } h ( 4 ) = 2$$ She then argues that since there is a change of sign there must be a value of \(x\) in the interval \(1 < x < 4\) that gives \(\mathrm { h } ( x ) = 0\) Explain the error in Alice's argument.
    [0pt] [2 marks]
    10
  3. By considering any turning points of h , determine whether h has an inverse function. Fully justify your answer.
    [0pt] [6 marks]