12 A particle has a speed of \(6 \mathrm {~ms} ^ { - 1 }\) in a direction relative to unit vectors \(\mathbf { i }\) and \(\mathbf { j }\) as shown in the diagram below.
\includegraphics[max width=\textwidth, alt={}, center]{b7df05bf-f3fc-4705-a13c-6b562896fa9f-18_307_542_1528_749}
The velocity of this particle can be expressed as a vector \(\left[ \begin{array} { l } v _ { 1 } \\ v _ { 2 } \end{array} \right] \mathrm { ms } ^ { - 1 }\)
Find the correct expression for \(v _ { 2 }\)
Circle your answer.
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Question 12:
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Guidance
Answer/Working Mark
Guidance
\(v_2 = 6\sin 30°\) B1 (AO1.1b)
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## Question 12:
| Answer/Working | Mark | Guidance |
|---|---|---|
| $v_2 = 6\sin 30°$ | B1 (AO1.1b) | Circles correct answer |
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12 A particle has a speed of $6 \mathrm {~ms} ^ { - 1 }$ in a direction relative to unit vectors $\mathbf { i }$ and $\mathbf { j }$ as shown in the diagram below.\\
\includegraphics[max width=\textwidth, alt={}, center]{b7df05bf-f3fc-4705-a13c-6b562896fa9f-18_307_542_1528_749}
The velocity of this particle can be expressed as a vector $\left[ \begin{array} { l } v _ { 1 } \\ v _ { 2 } \end{array} \right] \mathrm { ms } ^ { - 1 }$\\
Find the correct expression for $v _ { 2 }$\\
Circle your answer.\\[0pt]
[1 mark]\\
$v _ { 2 } = 6 \cos 30 ^ { \circ }$\\
$v _ { 2 } = 6 \sin 30 ^ { \circ }$\\
$v _ { 2 } = - 6 \sin 30 ^ { \circ }$\\
$v _ { 2 } = - 6 \cos 30 ^ { \circ }$
\hfill \mbox{\textit{AQA Paper 2 2021 Q12 [1]}}