Moderate -0.8 This is a straightforward two-step problem: use a SUVAT equation (v² = u² + 2as) to find acceleration, then apply F = ma. Both are standard procedures with no conceptual difficulty or problem-solving required, making it easier than average but not trivial since it requires correct equation selection and two-step execution.
13 A vehicle, of total mass 1200 kg , is travelling along a straight, horizontal road at a constant speed of \(13 \mathrm {~m} \mathrm {~s} ^ { - 1 }\)
This vehicle begins to accelerate at a constant rate.
After 40 metres it reaches a speed of \(17 \mathrm {~ms} ^ { - 1 }\)
Find the resultant force acting on the vehicle during the period of acceleration.
13 A vehicle, of total mass 1200 kg , is travelling along a straight, horizontal road at a constant speed of $13 \mathrm {~m} \mathrm {~s} ^ { - 1 }$
This vehicle begins to accelerate at a constant rate.\\
After 40 metres it reaches a speed of $17 \mathrm {~ms} ^ { - 1 }$\\
Find the resultant force acting on the vehicle during the period of acceleration.\\
\hfill \mbox{\textit{AQA Paper 2 2021 Q13 [3]}}