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Edexcel Paper 2 2023 June Q7
  1. In this question you must show all stages of your working.
Solutions relying on calculator technology are not acceptable.
A curve has equation $$x ^ { 3 } + 2 x y + 3 y ^ { 2 } = 47$$
  1. Find \(\frac { \mathrm { d } y } { \mathrm {~d} x }\) in terms of \(x\) and \(y\) The point \(P ( - 2,5 )\) lies on the curve.
  2. Find the equation of the normal to the curve at \(P\), giving your answer in the form \(a x + b y + c = 0\), where \(a , b\) and \(c\) are integers to be found.
Edexcel Paper 2 2023 June Q8
  1. (a) Express \(2 \cos \theta + 8 \sin \theta\) in the form \(R \cos ( \theta - \alpha )\), where \(R\) and \(\alpha\) are constants, \(R > 0\) and \(0 < \alpha < \frac { \pi } { 2 }\)
    Give the exact value of \(R\) and give the value of \(\alpha\) in radians to 3 decimal places.
The first three terms of an arithmetic sequence are $$\cos x \quad \cos x + \sin x \quad \cos x + 2 \sin x \quad x \neq n \pi$$ Given that \(S _ { 9 }\) represents the sum of the first 9 terms of this sequence as \(x\) varies,
(b) (i) find the exact maximum value of \(S _ { 9 }\)
(ii) deduce the smallest positive value of \(x\) at which this maximum value of \(S _ { 9 }\) occurs.
Edexcel Paper 2 2023 June Q9
  1. The curve \(C\) has parametric equations
$$x = t ^ { 2 } + 6 t - 16 \quad y = 6 \ln ( t + 3 ) \quad t > - 3$$
  1. Show that a Cartesian equation for \(C\) is $$y = A \ln ( x + B ) \quad x > - B$$ where \(A\) and \(B\) are integers to be found. The curve \(C\) cuts the \(y\)-axis at the point \(P\)
  2. Show that the equation of the tangent to \(C\) at \(P\) can be written in the form $$a x + b y = c \ln 5$$ where \(a\), \(b\) and \(c\) are integers to be found.
Edexcel Paper 2 2023 June Q10
  1. \(\mathrm { f } ( x ) = \frac { 3 k x - 18 } { ( x + 4 ) ( x - 2 ) } \quad\) where \(k\) is a positive constant
    1. Express \(\mathrm { f } ( x )\) in partial fractions in terms of \(k\).
    2. Hence find the exact value of \(k\) for which
    $$\int _ { - 3 } ^ { 1 } f ( x ) d x = 21$$
Edexcel Paper 2 2023 June Q11
11. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{3f6f3f19-a1d0-488b-a1a4-302cc4cf5a1e-30_455_997_210_552} \captionsetup{labelformat=empty} \caption{Figure 1}
\end{figure} A tank in the shape of a cuboid is being filled with water.
The base of the tank measures 20 m by 10 m and the height of the tank is 5 m , as shown in Figure 1. At time \(t\) minutes after water started flowing into the tank the height of the water was \(h \mathrm {~m}\) and the volume of water in the tank was \(V \mathrm {~m} ^ { 3 }\) In a model of this situation
  • the sides of the tank have negligible thickness
  • the rate of change of \(V\) is inversely proportional to the square root of \(h\)
    1. Show that
$$\frac { \mathrm { d } h } { \mathrm {~d} t } = \frac { \lambda } { \sqrt { h } }$$ where \(\lambda\) is a constant. Given that
  • initially the height of the water in the tank was 1.44 m
  • exactly 8 minutes after water started flowing into the tank the height of the water was 3.24 m
  • use the model to find an equation linking \(h\) with \(t\), giving your answer in the form
$$h ^ { \frac { 3 } { 2 } } = A t + B$$ where \(A\) and \(B\) are constants to be found.
  • Hence find the time taken, from when water started flowing into the tank, for the tank to be completely full.
  • Edexcel Paper 2 2023 June Q12
    12. \begin{figure}[h]
    \includegraphics[alt={},max width=\textwidth]{3f6f3f19-a1d0-488b-a1a4-302cc4cf5a1e-34_643_652_210_708} \captionsetup{labelformat=empty} \caption{Figure 2}
    \end{figure} The number of subscribers to two different music streaming companies is being monitored. The number of subscribers, \(N _ { \mathrm { A } }\), in thousands, to company \(\mathbf { A }\) is modelled by the equation $$N _ { \mathrm { A } } = | t - 3 | + 4 \quad t \geqslant 0$$ where \(t\) is the time in years since monitoring began.
    The number of subscribers, \(N _ { \mathrm { B } }\), in thousands, to company B is modelled by the equation $$N _ { \mathrm { B } } = 8 - | 2 t - 6 | \quad t \geqslant 0$$ where \(t\) is the time in years since monitoring began.
    Figure 2 shows a sketch of the graph of \(N _ { \mathrm { A } }\) and the graph of \(N _ { \mathrm { B } }\) over a 5-year period.
    Use the equations of the models to answer parts (a), (b), (c) and (d).
    1. Find the initial difference between the number of subscribers to company \(\mathbf { A }\) and the number of subscribers to company B. When \(t = T\) company A reduced its subscription prices and the number of subscribers increased.
    2. Suggest a value for \(T\), giving a reason for your answer.
    3. Find the range of values of \(t\) for which \(N _ { \mathrm { A } } > N _ { \mathrm { B } }\) giving your answer in set notation.
    4. State a limitation of the model used for company B.
    Edexcel Paper 2 2023 June Q13
    1. In this question you must show all stages of your working. Solutions relying entirely on calculator technology are not acceptable.
      1. Find the first three terms, in ascending powers of \(x\), of the binomial expansion of
      $$( 3 + x ) ^ { - 2 }$$ writing each term in simplest form.
    2. Using the answer to part (a) and using algebraic integration, estimate the value of $$\int _ { 0.2 } ^ { 0.4 } \frac { 6 x } { ( 3 + x ) ^ { 2 } } d x$$ giving your answer to 4 significant figures.
    3. Find, using algebraic integration, the exact value of $$\int _ { 0.2 } ^ { 0.4 } \frac { 6 x } { ( 3 + x ) ^ { 2 } } d x$$ giving your answer in the form \(a \ln b + c\), where \(a , b\) and \(c\) are constants to be found.
    Edexcel Paper 2 2023 June Q14
    1. In this question you must show all stages of your working.
    Solutions relying entirely on calculator technology are not acceptable.
    1. Show that the equation $$2 \tan \theta \left( 8 \cos \theta + 23 \sin ^ { 2 } \theta \right) = 8 \sin 2 \theta \left( 1 + \tan ^ { 2 } \theta \right)$$ may be written as $$\sin 2 \theta \left( A \cos ^ { 2 } \theta + B \cos \theta + C \right) = 0$$ where \(A , B\) and \(C\) are constants to be found.
    2. Hence, solve for \(360 ^ { \circ } \leqslant x \leqslant 540 ^ { \circ }\) $$2 \tan x \left( 8 \cos x + 23 \sin ^ { 2 } x \right) = 8 \sin 2 x \left( 1 + \tan ^ { 2 } x \right) \quad x \in \mathbb { R } \quad x \neq 450 ^ { \circ }$$
    Edexcel Paper 2 2023 June Q15
    1. A student attempts to answer the following question:
    Given that \(x\) is an obtuse angle, use algebra to prove by contradiction that $$\sin x - \cos x \geqslant 1$$ The student starts the proof with: Assume that \(\sin x - \cos x < 1\) when \(x\) is an obtuse angle $$\begin{aligned} & \Rightarrow ( \sin x - \cos x ) ^ { 2 } < 1
    & \Rightarrow \ldots \end{aligned}$$ The start of the student's proof is reprinted below.
    Complete the proof. Assume that \(\sin x - \cos x < 1\) when \(x\) is an obtuse angle $$\Rightarrow ( \sin x - \cos x ) ^ { 2 } < 1$$
    Edexcel Paper 2 2024 June Q1
    1. $$y = 4 x ^ { 3 } - 7 x ^ { 2 } + 5 x - 10$$
    1. Find in simplest form
      1. \(\frac { \mathrm { d } y } { \mathrm {~d} x }\)
      2. \(\frac { \mathrm { d } ^ { 2 } y } { \mathrm {~d} x ^ { 2 } }\)
    2. Hence find the exact value of \(x\) when \(\frac { \mathrm { d } ^ { 2 } y } { \mathrm {~d} x ^ { 2 } } = 0\)
    Edexcel Paper 2 2024 June Q2
    1. Jamie takes out an interest-free loan of \(\pounds 8100\)
    Jamie makes a payment every month to pay back the loan.
    Jamie repays \(\pounds 400\) in month \(1 , \pounds 390\) in month \(2 , \pounds 380\) in month 3 , and so on, so that the amounts repaid each month form an arithmetic sequence.
    1. Show that Jamie repays \(\pounds 290\) in month 12 After Jamie's \(N\) th payment, the loan is completely paid back.
    2. Show that \(N ^ { 2 } - 81 N + 1620 = 0\)
    3. Hence find the value of \(N\).
    Edexcel Paper 2 2024 June Q3
    1. The point \(P ( 3 , - 2 )\) lies on the curve with equation \(y = \mathrm { f } ( x ) , x \in \mathbb { R }\)
    Find the coordinates of the point to which \(P\) is mapped when the curve with equation \(y = \mathrm { f } ( x )\) is transformed to the curve with equation
    1. \(y = \mathrm { f } ( x - 2 )\)
    2. \(y = \mathrm { f } ( 2 x )\)
    3. \(y = 3 \mathrm { f } ( - x ) + 5\)
    Edexcel Paper 2 2024 June Q4
    1. A sequence \(u _ { 1 } , u _ { 2 } , u _ { 3 } , \ldots\) is defined by
    $$\begin{aligned} u _ { n + 1 } & = k u _ { n } - 5
    u _ { 1 } & = 6 \end{aligned}$$ where \(k\) is a positive constant.
    Given that \(u _ { 3 } = - 1\)
    1. show that $$6 k ^ { 2 } - 5 k - 4 = 0$$
    2. Hence
      1. find the value of \(k\),
      2. find the value of \(\sum _ { r = 1 } ^ { 3 } u _ { r }\)
    Edexcel Paper 2 2024 June Q5
    1. Given that \(\theta\) is small and in radians, use the small angle approximations to find an approximate numerical value of
    $$\frac { \theta \tan 2 \theta } { 1 - \cos 3 \theta }$$
    Edexcel Paper 2 2024 June Q6
    6. \begin{figure}[h]
    \includegraphics[alt={},max width=\textwidth]{2ce10759-9ce6-47a1-b55d-d22082f88f55-12_518_670_248_740} \captionsetup{labelformat=empty} \caption{Figure 1}
    \end{figure} Figure 1 shows a sketch of the curves with equations \(y = \mathrm { f } ( x )\) and \(y = \mathrm { g } ( x )\) where $$\begin{array} { l l } \mathrm { f } ( x ) = \mathrm { e } ^ { 4 x ^ { 2 } - 1 } & x > 0
    \mathrm {~g} ( x ) = 8 \ln x & x > 0 \end{array}$$
    1. Find
      1. \(\mathrm { f } ^ { \prime } ( x )\)
      2. \(\mathrm { g } ^ { \prime } ( x )\) Given that \(\mathrm { f } ^ { \prime } ( x ) = \mathrm { g } ^ { \prime } ( x )\) at \(x = \alpha\)
    2. show that \(\alpha\) satisfies the equation $$4 x ^ { 2 } + 2 \ln x - 1 = 0$$ The iterative formula $$x _ { n + 1 } = \sqrt { \frac { 1 - 2 \ln x _ { n } } { 4 } }$$ is used with \(x _ { 1 } = 0.6\) to find an approximate value for \(\alpha\)
    3. Calculate, giving each answer to 4 decimal places,
      1. the value of \(x _ { 2 }\)
      2. the value of \(\alpha\)
    Edexcel Paper 2 2024 June Q7
    7. \begin{figure}[h]
    \includegraphics[alt={},max width=\textwidth]{2ce10759-9ce6-47a1-b55d-d22082f88f55-16_330_654_246_751} \captionsetup{labelformat=empty} \caption{Figure 2}
    \end{figure} Figure 2 shows a sketch of the straight line \(l\).
    Line \(l\) passes through the points \(A\) and \(B\).
    Relative to a fixed origin \(O\)
    • the point \(A\) has position vector \(2 \mathbf { i } - 3 \mathbf { j } + 5 \mathbf { k }\)
    • the point \(B\) has position vector \(5 \mathbf { i } + 6 \mathbf { j } + 8 \mathbf { k }\)
      1. Find \(\overrightarrow { A B }\)
    Given that a point \(P\) lies on \(l\) such that $$| \overrightarrow { A P } | = 2 | \overrightarrow { B P } |$$
  • find the possible position vectors of \(P\).
  • Edexcel Paper 2 2024 June Q8
    1. In this question you must show all stages of your working.
    Solutions relying entirely on calculator technology are not acceptable.
    1. Prove that $$\frac { 1 } { \operatorname { cosec } \theta - 1 } + \frac { 1 } { \operatorname { cosec } \theta + 1 } \equiv 2 \tan \theta \sec \theta \quad \theta \neq ( 90 n ) ^ { \circ } , n \in \mathbb { Z }$$
    2. Hence solve, for \(0 < x < 90 ^ { \circ }\), the equation $$\frac { 1 } { \operatorname { cosec } 2 x - 1 } + \frac { 1 } { \operatorname { cosec } 2 x + 1 } = \cot 2 x \sec 2 x$$ Give each answer, in degrees, to one decimal place.
    Edexcel Paper 2 2024 June Q9
    9. \begin{figure}[h]
    \includegraphics[alt={},max width=\textwidth]{2ce10759-9ce6-47a1-b55d-d22082f88f55-22_595_1058_248_466} \captionsetup{labelformat=empty} \caption{Figure 3}
    \end{figure} The graph in Figure 3 shows the path of a small ball.
    The ball travels in a vertical plane above horizontal ground.
    The ball is thrown from the point represented by \(A\) and caught at the point represented by \(B\). The height, \(H\) metres, of the ball above the ground has been plotted against the horizontal distance, \(x\) metres, measured from the point where the ball was thrown. With respect to a fixed origin \(O\), the point \(A\) has coordinates \(( 0,2 )\) and the point \(B\) has coordinates (20, 0.8), as shown in Figure 3. The ball reaches its maximum height when \(x = 9\)
    A quadratic function, linking \(H\) with \(x\), is used to model the path of the ball.
    1. Find \(H\) in terms of \(x\).
    2. Give one limitation of the model. Chandra is standing directly under the path of the ball at a point 16 m horizontally from \(O\). Chandra can catch the ball if the ball is less than 2.5 m above the ground.
    3. Use the model to determine if Chandra can catch the ball.
    Edexcel Paper 2 2024 June Q10
    10. \begin{figure}[h]
    \includegraphics[alt={},max width=\textwidth]{2ce10759-9ce6-47a1-b55d-d22082f88f55-26_707_992_246_539} \captionsetup{labelformat=empty} \caption{Figure 4}
    \end{figure} Figure 4 shows a sketch of the curve \(C\) with parametric equations $$x = ( t + 3 ) ^ { 2 } \quad y = 1 - t ^ { 3 } \quad - 2 \leqslant t \leqslant 1$$ The point \(P\) with coordinates \(( 4,2 )\) lies on \(C\).
    1. Using parametric differentiation, show that the tangent to \(C\) at \(P\) has equation $$3 x + 4 y = 20$$ The curve \(C\) is used to model the profile of a slide at a water park.
      Units are in metres, with \(y\) being the height of the slide above water level.
    2. Find, according to the model, the greatest height of the slide above water level.
    Edexcel Paper 2 2024 June Q11
    11. \begin{figure}[h]
    \includegraphics[alt={},max width=\textwidth]{2ce10759-9ce6-47a1-b55d-d22082f88f55-28_668_743_251_662} \captionsetup{labelformat=empty} \caption{Figure 5}
    \end{figure} In this question you must show all stages of your working. Solutions relying entirely on calculator technology are not acceptable. Figure 5 shows a sketch of part of the curve \(C\) with equation $$y = 8 x ^ { 2 } \mathrm { e } ^ { - 3 x } \quad x \geqslant 0$$ The finite region \(R\), shown shaded in Figure 5, is bounded by
    • the curve \(C\)
    • the line with equation \(x = 1\)
    • the \(x\)-axis
    Find the exact area of \(R\), giving your answer in the form $$A + B \mathrm { e } ^ { - 3 }$$ where \(A\) and \(B\) are rational numbers to be found.
    Edexcel Paper 2 2024 June Q12
    1. (a) Express \(\frac { 1 } { V ( 25 - V ) }\) in partial fractions.
    The volume, \(V\) microlitres, of a plant cell \(t\) hours after the plant is watered is modelled by the differential equation $$\frac { \mathrm { d } V } { \mathrm {~d} t } = \frac { 1 } { 10 } V ( 25 - V )$$ The plant cell has an initial volume of 20 microlitres.
    (b) Find, according to the model, the time taken, in minutes, for the volume of the plant cell to reach 24 microlitres.
    (c) Show that $$V = \frac { A } { \mathrm { e } ^ { - k t } + B }$$ where \(A , B\) and \(k\) are constants to be found. The model predicts that there is an upper limit, \(L\) microlitres, on the volume of the plant cell.
    (d) Find the value of \(L\), giving a reason for your answer.
    Edexcel Paper 2 2024 June Q13
    1. The world human population, \(P\) billions, is modelled by the equation
    $$P = a b ^ { t }$$ where \(a\) and \(b\) are constants and \(t\) is the number of years after 2004
    Using the estimated population figures for the years from 2004 to 2007, a graph is plotted of \(\log _ { 10 } P\) against \(t\). The points lie approximately on a straight line with
    • gradient 0.0054
    • intercept 0.81 on the \(\log _ { 10 } P\) axis
      1. Estimate, to 3 decimal places, the value of \(a\) and the value of \(b\).
    In the context of the model,
    1. interpret the value of the constant \(a\),
    2. interpret the value of the constant \(b\).
  • Use the model to estimate the world human population in 2030
  • Comment on the reliability of the answer to part (c).
  • Edexcel Paper 2 2024 June Q14
    1. The circle \(C _ { 1 }\) has equation
    $$x ^ { 2 } + y ^ { 2 } - 6 x + 14 y + 33 = 0$$
    1. Find
      1. the coordinates of the centre of \(C _ { 1 }\)
      2. the radius of \(C _ { 1 }\) A different circle \(C _ { 2 }\)
        • has centre with coordinates (-6, -8)
    2. has radius \(k\), where \(k\) is a constant
    3. Given that \(C _ { 1 }\) and \(C _ { 2 }\) intersect at 2 distinct points,
    4. find the range of values of \(k\), writing your answer in set notation.
    Edexcel Paper 2 2024 June Q15
    1. The curve \(C\) has equation
    $$( x + y ) ^ { 3 } = 3 x ^ { 2 } - 3 y - 2$$
    1. Find an expression for \(\frac { \mathrm { d } y } { \mathrm {~d} x }\) in terms of \(x\) and \(y\). The point \(P ( 1,0 )\) lies on \(C\).
    2. Show that the normal to \(C\) at \(P\) has equation $$y = - 2 x + 2$$
    3. Prove that the normal to \(C\) at \(P\) does not meet \(C\) again. You should use algebra for your proof and make your reasoning clear.
    Edexcel Paper 2 2020 October Q1
    1 The table below shows corresponding values of \(x\) and \(y\) for \(y = \sqrt { \frac { x } { 1 + x } }\)
    The values of \(y\) are given to 4 significant figures.
    \(x\)0.511.522.5
    \(y\)0.57740.70710.77460.81650.8452
    1. Use the trapezium rule, with all the values of \(y\) in the table, to find an estimate for $$\int _ { 0.5 } ^ { 2.5 } \sqrt { \frac { x } { 1 + x } } \mathrm {~d} x$$ giving your answer to 3 significant figures.
    2. Using your answer to part (a), deduce an estimate for \(\int _ { 0.5 } ^ { 2.5 } \sqrt { \frac { 9 x } { 1 + x } } \mathrm {~d} x\) Given that $$\int _ { 0.5 } ^ { 2.5 } \sqrt { \frac { 9 x } { 1 + x } } \mathrm {~d} x = 4.535 \text { to } 4 \text { significant figures }$$
    3. comment on the accuracy of your answer to part (b).