| Exam Board | Edexcel |
|---|---|
| Module | Paper 2 (Paper 2) |
| Year | 2024 |
| Session | June |
| Marks | 9 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Exponential Equations & Modelling |
| Type | log(y) vs x: convert and interpret |
| Difficulty | Standard +0.3 This is a standard log-linear modelling question requiring students to convert between exponential and linear forms using logarithms. The steps are routine: use intercept to find a (10^0.81), use gradient to find b (10^0.0054), interpret constants, and substitute t=26. Part (d) requires basic understanding of model limitations. Slightly easier than average due to clear scaffolding and standard technique. |
| Spec | 1.06h Logarithmic graphs: reduce y=ax^n and y=kb^x to linear form |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| \(\log_{10} b = 0.0054 \Rightarrow b = 10^{0.0054}\) or \(\log_{10} a = 0.81 \Rightarrow a = 10^{0.81}\) | M1 | Must use base 10; may be implied by \(a \approx\) awrt 6.46 or \(b \approx\) awrt 1.01 |
| \(b = 1.01\) or \(a = 6.46\) | A1 | Allow 3 sf |
| \(\log_{10} b = 0.0054 \Rightarrow b = 10^{0.0054}\) and \(\log_{10} a = 0.81 \Rightarrow a = 10^{0.81}\) | M1 | Both values; may be implied if no incorrect work seen |
| \(b = 1.013\) and \(a = 6.457\) | A1 | Requires \(a =\) awrt 6.457 and \(b =\) awrt 1.013; isw once correct answers seen |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| e.g. The world population in billions in 2004 | B1ft | Follow through their \(a\); must reference "billions"; allow "original/initial population in billions" |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| \(b = 1.013\) represents the scale factor of the yearly increase in the world population | B1ft | Follow through their \(b\); must reference "each year" or "yearly"; allow "proportional increase/change in each year", "population rises by 1.3% each year", "multiplier representing year on year increase" |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| \(P = 6.457...(1.013...)^{26}\) or \(\log P = 0.81 + 26\times 0.0054 \Rightarrow P = ...\) | M1 | Substitutes \(t = 25, 26\) or \(27\); must use their \(a\) and \(b\) correctly in \(P = ab^t\) |
| awrt 9 billion | A1 | From correct model; condone incorrect/premature rounding leading to awrt 9 billion; allow \(9\,000\,000\,000\) or \(9\times10^9\); just "9" without "billions" is A0 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| Not reliable since data used for model covered 2004–2007 and it would not be sensible to assume the model still holds in 2030 | B1 | Must refer to unreliability and reference data being a long way from 2030 |
## Question 13:
### Part (a):
| Answer/Working | Mark | Guidance |
|---|---|---|
| $\log_{10} b = 0.0054 \Rightarrow b = 10^{0.0054}$ **or** $\log_{10} a = 0.81 \Rightarrow a = 10^{0.81}$ | M1 | Must use base 10; may be implied by $a \approx$ awrt 6.46 or $b \approx$ awrt 1.01 |
| $b = 1.01$ **or** $a = 6.46$ | A1 | Allow 3 sf |
| $\log_{10} b = 0.0054 \Rightarrow b = 10^{0.0054}$ **and** $\log_{10} a = 0.81 \Rightarrow a = 10^{0.81}$ | M1 | Both values; may be implied if no incorrect work seen |
| $b = 1.013$ **and** $a = 6.457$ | A1 | Requires $a =$ awrt 6.457 and $b =$ awrt 1.013; isw once correct answers seen |
**Special case - constants wrong way round:** $a = 1.013$ **and** $b = 6.457$ scores M1A1M1A0 unless equation formed correctly.
---
### Part (b)(i):
| Answer/Working | Mark | Guidance |
|---|---|---|
| e.g. The world population **in billions** in 2004 | B1ft | Follow through their $a$; must reference "billions"; allow "original/initial population in billions" |
---
### Part (b)(ii):
| Answer/Working | Mark | Guidance |
|---|---|---|
| $b = 1.013$ represents the scale factor of the yearly increase in the world population | B1ft | Follow through their $b$; must reference "each year" or "yearly"; allow "proportional increase/change in each year", "population rises by 1.3% each year", "multiplier representing year on year increase" |
Do **not** accept: "the amount it is rising", "how much it is rising", "the rate the population increases", "the percentage increase each year", "the rate of increase in billions annually"
---
### Part (c):
| Answer/Working | Mark | Guidance |
|---|---|---|
| $P = 6.457...(1.013...)^{26}$ or $\log P = 0.81 + 26\times 0.0054 \Rightarrow P = ...$ | M1 | Substitutes $t = 25, 26$ or $27$; must use **their** $a$ and $b$ correctly in $P = ab^t$ |
| awrt 9 billion | A1 | From correct model; condone incorrect/premature rounding leading to awrt 9 billion; allow $9\,000\,000\,000$ or $9\times10^9$; just "9" without "billions" is A0 |
---
### Part (d):
| Answer/Working | Mark | Guidance |
|---|---|---|
| Not reliable since data used for model covered 2004–2007 and it would not be sensible to assume the model still holds in 2030 | B1 | Must refer to unreliability **and** reference data being a long way from 2030 |
Accept: "Not good as 2030 is a long way from 2004–2007", "unreliable as based on old data", "questionable as extrapolated over a long time", "not reliable due to how far we have extrapolated"
Do **not** accept: "unreliable, extrapolation" (alone), "not good as outside the range", "disease may happen", "reliable as based on old data"
---
\begin{enumerate}
\item The world human population, $P$ billions, is modelled by the equation
\end{enumerate}
$$P = a b ^ { t }$$
where $a$ and $b$ are constants and $t$ is the number of years after 2004\\
Using the estimated population figures for the years from 2004 to 2007, a graph is plotted of $\log _ { 10 } P$ against $t$.
The points lie approximately on a straight line with
\begin{itemize}
\item gradient 0.0054
\item intercept 0.81 on the $\log _ { 10 } P$ axis\\
(a) Estimate, to 3 decimal places, the value of $a$ and the value of $b$.
\end{itemize}
In the context of the model,\\
(b) (i) interpret the value of the constant $a$,\\
(ii) interpret the value of the constant $b$.\\
(c) Use the model to estimate the world human population in 2030\\
(d) Comment on the reliability of the answer to part (c).
\hfill \mbox{\textit{Edexcel Paper 2 2024 Q13 [9]}}