Last year Eleanor played 11 rounds of golf. Her scores were as follows:
79, 71, 80, 67, 67, 74, 66, 65, 71, 66, 64.
- Calculate the mean of these scores and show that the standard deviation is 5.31, correct to 3 significant figures. [4]
- Find the median and interquartile range of the scores. [4]
This year, Eleanor also played 11 rounds of golf. The standard deviation of her scores was 4.23, correct to 3 significant figures, and the interquartile range was the same as last year.
- Give a possible reason why the standard deviation of her scores was lower than last year although her interquartile range was unchanged. [1]
In golf, smaller scores mean a better standard of play than larger scores. Ken suggests that since the standard deviation was smaller this year, Eleanor's overall standard has improved.
- Explain why Ken is wrong. [1]
- State what the smaller standard deviation does show about Eleanor's play. [1]