AQA S1 2007 January — Question 7 15 marks

Exam BoardAQA
ModuleS1 (Statistics 1)
Year2007
SessionJanuary
Marks15
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicLinear regression
TypeCalculate y on x from raw data table
DifficultyModerate -0.8 This is a straightforward S1 linear regression question requiring standard calculations (Sxx, Sxy, finding a and b) from a small dataset, plotting points, and interpreting the result. All steps are routine textbook procedures with no conceptual challenges or novel problem-solving required.
Spec5.09b Least squares regression: concepts5.09c Calculate regression line5.09e Use regression: for estimation in context

7 [Figure 1, printed on the insert, is provided for use in this question.]
Stan is a retired academic who supplements his pension by mowing lawns for customers who live nearby. As part of a review of his charges for this work, he measures the areas, \(x \mathrm {~m} ^ { 2 }\), of a random sample of eight of his customers' lawns and notes the times, \(y\) minutes, that it takes him to mow these lawns. His results are shown in the table.
Customer\(\mathbf { A }\)\(\mathbf { B }\)\(\mathbf { C }\)\(\mathbf { D }\)\(\mathbf { E }\)\(\mathbf { F }\)\(\mathbf { G }\)\(\mathbf { H }\)
\(\boldsymbol { x }\)3601408606001180540260480
\(\boldsymbol { y }\)502513570140905570
  1. On Figure 1, plot a scatter diagram of these data.
  2. Calculate the equation of the least squares regression line of \(y\) on \(x\). Draw your line on Figure 1.
  3. Calculate the value of the residual for Customer H and indicate how your value is confirmed by your scatter diagram.
  4. Given that Stan charges \(\pounds 12\) per hour, estimate the charge for mowing a customer's lawn that has an area of \(560 \mathrm {~m} ^ { 2 }\).

Question 7:
Part 7(a):
AnswerMarks Guidance
AnswerMark Guidance
8 or 7 points plotted accuratelyB2
(6 or 5 points plotted accurately)(B1)
Part 7(b):
AnswerMarks Guidance
AnswerMark Guidance
Gradient, \(b = 0.114\) to \(0.115\)B2 AWFW (0.11469)
\((b = 0.11\) to \(0.12)\)(B1)
Intercept, \(a = 15.9\) to \(16.1\)B2 AWFW (16.00824)
\((a = 13\) to \(19)\)(B1)
Attempt at \(\sum x\), \(\sum x^2\), \(\sum y\) and \(\sum xy\) or attempt at \(S_{xx}\) and \(S_{xy}\)(M1) 4420, 3230800, 635 and 441300; 788750 and 90462.5
Attempt at correct formula for \(b\); \(b = 0.114\) to \(0.115\); \(a = 15.9\) to \(16.1\)(m1)(A1)(A1) AWFW; AWFW
Line plotted accurately (Evidence of correct method for \(\geq 2\) points)B2 (M1) At least from \(x = 200\) to \(1000\)
Part 7(c):
AnswerMarks Guidance
AnswerMark Guidance
\(\text{Res}_H = y_H - Y_H = 70 - (a + b \times 480)\)M1 Used; or implied by correct answer; allow for \(Y_H - y_H\) shown
\(= -1.5\) to \(-0.5\)A1 AWFW \((-1.06)\)
Point H is (almost) on / just below the lineB1 Accept near/close/just above or equivalent
Part 7(d):
AnswerMarks Guidance
AnswerMark Guidance
\(Y = a + b \times 560\) or reading from scatter diagramM1 Used
\(= 79\) to \(81\)A1 AWFW (80.2)
\(\text{Cost} = Y \times \frac{12}{60}\) or \(\frac{Y}{5}\)M1 Used
\(= £15.8\) to \(£16.2\)A1 AWFW; ignore units (£16.05)
# Question 7:

## Part 7(a):
| Answer | Mark | Guidance |
|--------|------|----------|
| 8 or 7 points plotted accurately | B2 | |
| (6 or 5 points plotted accurately) | (B1) | |

## Part 7(b):
| Answer | Mark | Guidance |
|--------|------|----------|
| Gradient, $b = 0.114$ to $0.115$ | B2 | AWFW (0.11469) |
| $(b = 0.11$ to $0.12)$ | (B1) | |
| Intercept, $a = 15.9$ to $16.1$ | B2 | AWFW (16.00824) |
| $(a = 13$ to $19)$ | (B1) | |
| Attempt at $\sum x$, $\sum x^2$, $\sum y$ and $\sum xy$ or attempt at $S_{xx}$ and $S_{xy}$ | (M1) | 4420, 3230800, 635 and 441300; 788750 and 90462.5 |
| Attempt at correct formula for $b$; $b = 0.114$ to $0.115$; $a = 15.9$ to $16.1$ | (m1)(A1)(A1) | AWFW; AWFW |
| Line plotted accurately (Evidence of correct method for $\geq 2$ points) | B2 (M1) | At least from $x = 200$ to $1000$ |

## Part 7(c):
| Answer | Mark | Guidance |
|--------|------|----------|
| $\text{Res}_H = y_H - Y_H = 70 - (a + b \times 480)$ | M1 | Used; or implied by correct answer; allow for $Y_H - y_H$ shown |
| $= -1.5$ to $-0.5$ | A1 | AWFW $(-1.06)$ |
| Point H is (almost) **on / just below** the line | B1 | Accept near/close/just above or equivalent |

## Part 7(d):
| Answer | Mark | Guidance |
|--------|------|----------|
| $Y = a + b \times 560$ or reading from scatter diagram | M1 | Used |
| $= 79$ to $81$ | A1 | AWFW (80.2) |
| $\text{Cost} = Y \times \frac{12}{60}$ or $\frac{Y}{5}$ | M1 | Used |
| $= £15.8$ to $£16.2$ | A1 | AWFW; ignore units (£16.05) |
7 [Figure 1, printed on the insert, is provided for use in this question.]\\
Stan is a retired academic who supplements his pension by mowing lawns for customers who live nearby.

As part of a review of his charges for this work, he measures the areas, $x \mathrm {~m} ^ { 2 }$, of a random sample of eight of his customers' lawns and notes the times, $y$ minutes, that it takes him to mow these lawns. His results are shown in the table.

\begin{center}
\begin{tabular}{ | c | c | c | c | c | c | c | c | c | }
\hline
Customer & $\mathbf { A }$ & $\mathbf { B }$ & $\mathbf { C }$ & $\mathbf { D }$ & $\mathbf { E }$ & $\mathbf { F }$ & $\mathbf { G }$ & $\mathbf { H }$ \\
\hline
$\boldsymbol { x }$ & 360 & 140 & 860 & 600 & 1180 & 540 & 260 & 480 \\
\hline
$\boldsymbol { y }$ & 50 & 25 & 135 & 70 & 140 & 90 & 55 & 70 \\
\hline
\end{tabular}
\end{center}
\begin{enumerate}[label=(\alph*)]
\item On Figure 1, plot a scatter diagram of these data.
\item Calculate the equation of the least squares regression line of $y$ on $x$. Draw your line on Figure 1.
\item Calculate the value of the residual for Customer H and indicate how your value is confirmed by your scatter diagram.
\item Given that Stan charges $\pounds 12$ per hour, estimate the charge for mowing a customer's lawn that has an area of $560 \mathrm {~m} ^ { 2 }$.
\end{enumerate}

\hfill \mbox{\textit{AQA S1 2007 Q7 [15]}}