CAIE
P2
2014
June
Q4
6 marks
Moderate -0.3
4 The parametric equations of a curve are
$$x = 2 \ln ( t + 1 ) , \quad y = 4 \mathrm { e } ^ { t }$$
Find the equation of the tangent to the curve at the point for which \(t = 0\). Give your answer in the form \(a x + b y + c = 0\), where \(a , b\) and \(c\) are integers.
CAIE
P2
2014
June
Q5
6 marks
Standard +0.3
5
\includegraphics[max width=\textwidth, alt={}, center]{de8af872-9f77-4787-8e66-ed199405ca25-2_583_597_1457_772}
The variables \(x\) and \(y\) satisfy the equation \(y = K \left( 2 ^ { p x } \right)\), where \(K\) and \(p\) are constants. The graph of \(\ln y\) against \(x\) is a straight line passing through the points ( \(1.35,1.87\) ) and ( \(3.35,3.81\) ), as shown in the diagram. Find the values of \(K\) and \(p\) correct to 2 decimal places.
[0pt]
[6]