CAIE P2 2014 June — Question 7 9 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2014
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFixed Point Iteration
TypeDerive equation from integral condition
DifficultyStandard +0.3 This is a straightforward multi-part question requiring routine integration, algebraic manipulation to rearrange for the given form, interval verification by substitution, and application of a provided iterative formula. All techniques are standard P2 content with no novel insight required—slightly easier than average due to the scaffolded structure and explicit guidance at each step.
Spec1.08a Fundamental theorem of calculus: integration as reverse of differentiation1.08c Integrate e^(kx), 1/x, sin(kx), cos(kx)1.08d Evaluate definite integrals: between limits1.09c Simple iterative methods: x_{n+1} = g(x_n), cobweb and staircase diagrams

7 It is given that \(\int _ { 0 } ^ { a } \left( \frac { 1 } { 2 } \mathrm { e } ^ { 3 x } + x ^ { 2 } \right) \mathrm { d } x = 10\), where \(a\) is a positive constant.
  1. Show that \(a = \frac { 1 } { 3 } \ln \left( 61 - 2 a ^ { 3 } \right)\).
  2. Show by calculation that the value of \(a\) lies between 1.0 and 1.5.
  3. Use an iterative formula, based on the equation in part (i), to find the value of \(a\) correct to 3 decimal places. Give the result of each iteration to 5 decimal places.

AnswerMarks
(i) Integrate to obtain \(ke^{3x} + mx^3\)M1
Apply both limits to obtain \(\frac{k}{3}e^{3t} + \frac{1}{3}a^3 - \frac{k}{3} = 10\) or equivalentA1
Rearrange to form involving natural logarithmDM1
Obtain \(a = \frac{3}{2}\ln(61 - 2a^3)\) with no errors seen (AG)A1 [4]
(ii) Consider sign of \(a - \frac{3}{2}\ln(61 - 2a^3)\) for \(1.0\) and \(1.5\) or equivalentM1
Obtain \(-0.36\) and \(0.17\) or equivalent and justify conclusionA1 [2]
(iii) Use iteration process correctly at least onceM1
Obtain final answer \(1.343\)A1
Show sufficient iterations to 5 decimal places to justify answer or show a sign change in the interval \((1.3425, 1.3435)\)A1 [3]
(i) Integrate to obtain $ke^{3x} + mx^3$ | M1 |
Apply both limits to obtain $\frac{k}{3}e^{3t} + \frac{1}{3}a^3 - \frac{k}{3} = 10$ or equivalent | A1 |
Rearrange to form involving natural logarithm | DM1 |
Obtain $a = \frac{3}{2}\ln(61 - 2a^3)$ with no errors seen (AG) | A1 [4] |

(ii) Consider sign of $a - \frac{3}{2}\ln(61 - 2a^3)$ for $1.0$ and $1.5$ or equivalent | M1 |
Obtain $-0.36$ and $0.17$ or equivalent and justify conclusion | A1 [2] |

(iii) Use iteration process correctly at least once | M1 |
Obtain final answer $1.343$ | A1 |
Show sufficient iterations to 5 decimal places to justify answer or show a sign change in the interval $(1.3425, 1.3435)$ | A1 [3] |
7 It is given that $\int _ { 0 } ^ { a } \left( \frac { 1 } { 2 } \mathrm { e } ^ { 3 x } + x ^ { 2 } \right) \mathrm { d } x = 10$, where $a$ is a positive constant.\\
(i) Show that $a = \frac { 1 } { 3 } \ln \left( 61 - 2 a ^ { 3 } \right)$.\\
(ii) Show by calculation that the value of $a$ lies between 1.0 and 1.5.\\
(iii) Use an iterative formula, based on the equation in part (i), to find the value of $a$ correct to 3 decimal places. Give the result of each iteration to 5 decimal places.

\hfill \mbox{\textit{CAIE P2 2014 Q7 [9]}}