CAIE P2 2014 June — Question 6 8 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2014
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicNumerical integration
TypeTrapezium rule with stated number of strips
DifficultyModerate -0.3 Part (a) is a straightforward integration of a rational function requiring a simple substitution or recognition of ln form, followed by basic logarithm manipulation. Part (b) is a standard trapezium rule application with clearly specified intervals. Both parts are routine A-level techniques with no problem-solving insight required, making this slightly easier than average.
Spec1.08c Integrate e^(kx), 1/x, sin(kx), cos(kx)1.08d Evaluate definite integrals: between limits1.09f Trapezium rule: numerical integration

6
  1. Show that \(\int _ { 6 } ^ { 16 } \frac { 6 } { 2 x - 7 } \mathrm {~d} x = \ln 125\).
  2. Use the trapezium rule with four intervals to find an approximation to $$\int _ { 1 } ^ { 17 } \log _ { 10 } x d x$$ giving your answer correct to 3 significant figures.

AnswerMarks Guidance
(a) Integrate to obtain form \(k\ln\left(2x - 7\right)\)M1
Obtain correct \(3\ln\left(2x - 7\right)\)A1
Substitute limits correctly (dependent on first M1)DM1
Use law for logarithm of a quotient or power (dependent on first M1)DM1
Confirm \(\ln 125\) following correct work and sufficient detail (AG)A1 [5]
(b) Evaluate \(y\) at \((1), 5, 9, 13, 17\)M1
Use correct formula, or equivalent, with \(h = 4\) and five \(y\)-valuesM1
Obtain \(13.5\)A1 [3]
**(a)** Integrate to obtain form $k\ln\left(2x - 7\right)$ | M1 |
Obtain correct $3\ln\left(2x - 7\right)$ | A1 |
Substitute limits correctly (dependent on first M1) | DM1 |
Use law for logarithm of a quotient or power (dependent on first M1) | DM1 |
Confirm $\ln 125$ following correct work and sufficient detail (AG) | A1 | [5]

**(b)** Evaluate $y$ at $(1), 5, 9, 13, 17$ | M1 |
Use correct formula, or equivalent, with $h = 4$ and five $y$-values | M1 |
Obtain $13.5$ | A1 | [3]
6
\begin{enumerate}[label=(\alph*)]
\item Show that $\int _ { 6 } ^ { 16 } \frac { 6 } { 2 x - 7 } \mathrm {~d} x = \ln 125$.
\item Use the trapezium rule with four intervals to find an approximation to

$$\int _ { 1 } ^ { 17 } \log _ { 10 } x d x$$

giving your answer correct to 3 significant figures.
\end{enumerate}

\hfill \mbox{\textit{CAIE P2 2014 Q6 [8]}}