5 The equation of a curve is
$$x ^ { 2 } - 2 x ^ { 2 } y + 3 y = 9$$
- Show that \(\frac { \mathrm { d } y } { \mathrm {~d} x } = \frac { 2 x - 4 x y } { 2 x ^ { 2 } - 3 }\).
- Find the equation of the normal to the curve at the point where \(x = 2\), giving your answer in the form \(a x + b y + c = 0\).