Questions — AQA Paper 1 (122 questions)

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AQA Paper 1 2018 June Q2
1 marks
2 The graph of \(y = 5 ^ { x }\) is transformed by a stretch in the \(y\)-direction, scale factor 5 State the equation of the transformed graph. Circle your answer.
[0pt] [1 mark]
\(y = 5 \times 5 ^ { x }\)
\(y = 5 ^ { \frac { x } { 5 } }\)
\(y = \frac { 1 } { 5 } \times 5 ^ { x }\)
\(y = 5 ^ { 5 x }\)
AQA Paper 1 2018 June Q3
3 A periodic sequence is defined by \(U _ { n } = \sin \left( \frac { n \pi } { 2 } \right)\)
State the period of this sequence. Circle your answer.
\(82 \pi \quad 4 \quad \pi\)
AQA Paper 1 2018 June Q4
4 The function f is defined by \(\mathrm { f } ( x ) = \mathrm { e } ^ { x - 4 } , x \in \mathbb { R }\)
Find \(\mathrm { f } ^ { - 1 } ( x )\) and state its domain.
AQA Paper 1 2018 June Q5
5 A curve is defined by the parametric equations $$\begin{aligned} & x = 4 \times 2 ^ { - t } + 3
& y = 3 \times 2 ^ { t } - 5 \end{aligned}$$ 5
  1. Show that \(\frac { \mathrm { d } y } { \mathrm {~d} x } = - \frac { 3 } { 4 } \times 2 ^ { 2 t }\)
    5
  2. Find the Cartesian equation of the curve in the form \(x y + a x + b y = c\), where \(a , b\) and \(c\) are integers.
AQA Paper 1 2018 June Q6
2 marks
6
  1. Find the first three terms, in ascending powers of \(x\), of the binomial expansion of \(\frac { 1 } { \sqrt { 4 + x } }\)
    6
  2. Hence, find the first three terms of the binomial expansion of \(\frac { 1 } { \sqrt { 4 - x ^ { 3 } } }\)
    6
    1. Edward, a student, decides to use this method to find a more accurate value for the integral by increasing the number of terms of the binomial expansion used. Explain clearly whether Edward's approximation will be an overestimate, an underestimate, or if it is impossible to tell.
      [0pt] [2 marks]
      6
  3. (ii) Edward goes on to use the expansion from part (b) to find an approximation for \(\int _ { - 2 } ^ { 0 } \frac { 1 } { \sqrt { 4 - x ^ { 3 } } } \mathrm {~d} x\) Explain why Edward's approximation is invalid.
AQA Paper 1 2018 June Q7
7 Three points \(A , B\) and \(C\) have coordinates \(A ( 8,17 ) , B ( 15,10 )\) and \(C ( - 2 , - 7 )\) 7
  1. Show that angle \(A B C\) is a right angle.
    7
  2. \(\quad A , B\) and \(C\) lie on a circle.
    7
    1. Explain why \(A C\) is a diameter of the circle.
      7
  3. (ii) Determine whether the point \(D ( - 8 , - 2 )\) lies inside the circle, on the circle or outside the circle. Fully justify your answer.
AQA Paper 1 2018 June Q8
8 The diagram shows a sector of a circle \(O A B\).
\(C\) is the midpoint of \(O B\).
Angle \(A O B\) is \(\theta\) radians.
\includegraphics[max width=\textwidth, alt={}, center]{85b10472-8149-4387-999f-2ef153f1a105-10_700_963_536_534} 8
  1. Given that the area of the triangle \(O A C\) is equal to one quarter of the area of the sector \(O A B\), show that \(\theta = 2 \sin \theta\)
    8
  2. Use the Newton-Raphson method with \(\theta _ { 1 } = \pi\), to find \(\theta _ { 3 }\) as an approximation for \(\theta\). Give your answer correct to five decimal places.
    8
  3. Given that \(\theta = 1.89549\) to five decimal places, find an estimate for the percentage error in the approximation found in part (b).
    Turn over for the next question
AQA Paper 1 2018 June Q9
9 An arithmetic sequence has first term \(a\) and common difference \(d\). The sum of the first 36 terms of the sequence is equal to the square of the sum of the first 6 terms. 9
  1. Show that \(4 a + 70 d = 4 a ^ { 2 } + 20 a d + 25 d ^ { 2 }\) 9
  2. Given that the sixth term of the sequence is 25 , find the smallest possible value of \(a\).
AQA Paper 1 2018 June Q10
10 A scientist is researching the effects of caffeine. She models the mass of caffeine in the body using $$m = m _ { 0 } \mathrm { e } ^ { - k t }$$ where \(m _ { 0 }\) milligrams is the initial mass of caffeine in the body and \(m\) milligrams is the mass of caffeine in the body after \(t\) hours. On average, it takes 5.7 hours for the mass of caffeine in the body to halve.
One cup of strong coffee contains 200 mg of caffeine.
10
  1. The scientist drinks two strong cups of coffee at 8 am. Use the model to estimate the mass of caffeine in the scientist's body at midday.
    10
  2. The scientist wants the mass of caffeine in her body to stay below 480 mg
    10
  3. Use the model to find the earliest time
    coffee.
    Give your answer to the nearest minute
AQA Paper 1 2018 June Q11
4 marks
11 The daily world production of oil can be modelled using $$V = 10 + 100 \left( \frac { t } { 30 } \right) ^ { 3 } - 50 \left( \frac { t } { 30 } \right) ^ { 4 }$$ where \(V\) is volume of oil in millions of barrels, and \(t\) is time in years since 1 January 1980. 11
    1. The model is used to predict the time, \(T\), when oil production will fall to zero.
      Show that \(T\) satisfies the equation $$T = \sqrt [ 3 ] { 60 T ^ { 2 } + \frac { 162000 } { T } }$$ 11
  1. (ii) Use the iterative formula \(T _ { n + 1 } = \sqrt [ 3 ] { 60 T _ { n } { } ^ { 2 } + \frac { 162000 } { T _ { n } } }\), with \(T _ { 0 } = 38\), to find the values of \(T _ { 1 } , T _ { 2 }\), and \(T _ { 3 }\), giving your answers to three decimal places.
    11
  2. (iii) Explain the relevance of using \(T _ { 0 } = 38\) 11
  3. From 1 January 1980 the daily use of oil by one technologically developing country can be modelled as $$V = 4.5 \times 1.063 ^ { t }$$ Use the models to show that the country's use of oil and the world production of oil will be equal during the year 2029.
    [0pt] [4 marks]
    \(12 \quad \mathrm { p } ( x ) = 30 x ^ { 3 } - 7 x ^ { 2 } - 7 x + 2\)
AQA Paper 1 2018 June Q12
12
  1. Prove that ( \(2 x + 1\) ) is a factor of \(\mathrm { p } ( x )\)
    12
  2. Factorise \(\mathrm { p } ( x )\) completely.
    12
  3. Prove that there are no real solutions to the equation $$\frac { 30 \sec ^ { 2 } x + 2 \cos x } { 7 } = \sec x + 1$$
AQA Paper 1 2018 June Q13
13 A company is designing a logo. The logo is a circle of radius 4 inches with an inscribed rectangle. The rectangle must be as large as possible. The company models the logo on an \(x - y\) plane as shown in the diagram.
\includegraphics[max width=\textwidth, alt={}, center]{85b10472-8149-4387-999f-2ef153f1a105-20_492_492_511_776} Use calculus to find the maximum area of the rectangle.
Fully justify your answer.
AQA Paper 1 2018 June Q14
14 Some students are trying to prove an identity for \(\sin ( A + B )\). They start by drawing two right-angled triangles \(O D E\) and \(O E F\), as shown.
\includegraphics[max width=\textwidth, alt={}, center]{85b10472-8149-4387-999f-2ef153f1a105-22_695_662_477_689} The students' incomplete proof continues,
Let angle \(D O E = A\) and angle \(E O F = B\).
In triangle OFR,
Line \(1 \quad \sin ( A + B ) = \frac { R F } { O F }\) Line 2 $$= \frac { R P + P F } { O F }$$ Line 3 $$= \frac { D E } { O F } + \frac { P F } { O F } \text { since } D E = R P$$ Line 4 $$= \frac { D E } { \cdots \cdots } \times \frac { \cdots \cdots } { O F } + \frac { P F } { E F } \times \frac { E F } { O F }$$ Line 5
\(=\) \(\_\_\_\_\) \(+ \cos A \sin B\) 14
  1. Explain why \(\frac { P F } { E F } \times \frac { E F } { O F }\) in Line 4 leads to \(\cos A \sin B\) in Line 5
    14
  2. Complete Line 4 and Line 5 to prove the identity Line 4 $$= \frac { D E } { \ldots \ldots } \times \frac { \cdots \ldots } { O F } + \frac { P F } { E F } \times \frac { E F } { O F }$$ Line 5 = \(+ \cos A \sin B\) 14
  3. Explain why the argument used in part (a) only proves the identity when \(A\) and \(B\) are acute angles. 14
  4. Another student claims that by replacing \(B\) with \(- B\) in the identity for \(\sin ( A + B )\) it is possible to find an identity for \(\sin ( A - B )\). Assuming the identity for \(\sin ( A + B )\) is correct for all values of \(A\) and \(B\), prove a similar result for \(\sin ( A - B )\).
AQA Paper 1 2018 June Q15
15 A curve has equation \(y = x ^ { 3 } - 48 x\) The point \(A\) on the curve has \(x\) coordinate - 4
The point \(B\) on the curve has \(x\) coordinate \(- 4 + h\)
15
  1. Show that the gradient of the line \(A B\) is \(h ^ { 2 } - 12 h\)
    15
  2. Explain how the result of part (a) can be used to show that \(A\) is a stationary point on the curve.
    \includegraphics[max width=\textwidth, alt={}, center]{85b10472-8149-4387-999f-2ef153f1a105-25_2488_1719_219_150}
    \includegraphics[max width=\textwidth, alt={}, center]{85b10472-8149-4387-999f-2ef153f1a105-26_2488_1719_219_150}
    \includegraphics[max width=\textwidth, alt={}, center]{85b10472-8149-4387-999f-2ef153f1a105-27_2488_1719_219_150}
    \includegraphics[max width=\textwidth, alt={}, center]{85b10472-8149-4387-999f-2ef153f1a105-28_2498_1721_213_150}
AQA Paper 1 2019 June Q1
1 marks
1 Given that \(a > 0\), determine which of these expressions is not equivalent to the others. Circle your answer.
[0pt] [1 mark] $$- 2 \log _ { 10 } \left( \frac { 1 } { a } \right) \quad 2 \log _ { 10 } ( a ) \quad \log _ { 10 } \left( a ^ { 2 } \right) \quad - 4 \log _ { 10 } ( \sqrt { a } )$$
AQA Paper 1 2019 June Q2
2 Given \(y = \mathrm { e } ^ { k x }\), where \(k\) is a constant, find \(\frac { \mathrm { d } y } { \mathrm {~d} x }\)
Circle your answer. $$\frac { \mathrm { d } y } { \mathrm {~d} x } = \mathrm { e } ^ { k x } \quad \frac { \mathrm {~d} y } { \mathrm {~d} x } = k \mathrm { e } ^ { k x } \quad \frac { \mathrm {~d} y } { \mathrm {~d} x } = k x \mathrm { e } ^ { k x - 1 } \quad \frac { \mathrm {~d} y } { \mathrm {~d} x } = \frac { \mathrm { e } ^ { k x } } { k }$$
AQA Paper 1 2019 June Q3
1 marks
3 The diagram below shows a sector of a circle.
\includegraphics[max width=\textwidth, alt={}, center]{6b1312f4-9a5c-4465-8129-7d37e99efefe-02_375_406_1647_817} The radius of the circle is 4 cm and \(\theta = 0.8\) radians. Find the area of the sector. Circle your answer.
[0pt] [1 mark]
\(1.28 \mathrm {~cm} ^ { 2 }\)
\(3.2 \mathrm {~cm} ^ { 2 }\)
\(6.4 \mathrm {~cm} ^ { 2 }\)
\(12.8 \mathrm {~cm} ^ { 2 }\)
AQA Paper 1 2019 June Q4
4 The point \(A\) has coordinates \(( - 1 , a )\) and the point \(B\) has coordinates \(( 3 , b )\) The line \(A B\) has equation \(5 x + 4 y = 17\)
Find the equation of the perpendicular bisector of the points \(A\) and \(B\).
AQA Paper 1 2019 June Q5
5 An arithmetic sequence has first term \(a\) and common difference \(d\). The sum of the first 16 terms of the sequence is 260 5
  1. Show that \(4 a + 30 d = 65\)
    5
  2. Given that the sum of the first 60 terms is 315 , find the sum of the first 41 terms.
    5
  3. \(\quad S _ { n }\) is the sum of the first \(n\) terms of the sequence. Explain why the value you found in part (b) is the maximum value of \(S _ { n }\)
AQA Paper 1 2019 June Q6
6 The function f is defined by $$\mathrm { f } ( x ) = \frac { 1 } { 2 } \left( x ^ { 2 } + 1 \right) , x \geq 0$$ 6
  1. Find the range of f . 6
    1. Find \(\mathrm { f } ^ { - 1 } ( x )\)
      6
  2. (ii) State the range of \(\mathrm { f } ^ { - 1 } ( x )\)
    6
  3. State the transformation which maps the graph of \(y = \mathrm { f } ( x )\) onto the graph of \(y = \mathrm { f } ^ { - 1 } ( x )\) 6
  4. Find the coordinates of the point of intersection of the graphs of \(y = \mathrm { f } ( x )\) and \(y = \mathrm { f } ^ { - 1 } ( x )\)
AQA Paper 1 2019 June Q7
2 marks
7
  1. By sketching the graphs of \(y = \frac { 1 } { x }\) and \(y = \sec 2 x\) on the axes below, show that the equation $$\frac { 1 } { x } = \sec 2 x$$ has exactly one solution for \(x > 0\)
    \includegraphics[max width=\textwidth, alt={}, center]{6b1312f4-9a5c-4465-8129-7d37e99efefe-08_675_771_689_639} 7
  2. By considering a suitable change of sign, show that the solution to the equation lies between 0.4 and 0.6
    7
  3. Show that the equation can be rearranged to give $$x = \frac { 1 } { 2 } \cos ^ { - 1 } x$$ 7
    1. Use the iterative formula $$x _ { n + 1 } = \frac { 1 } { 2 } \cos ^ { - 1 } x _ { n }$$ with \(x _ { 1 } = 0.4\), to find \(x _ { 2 } , x _ { 3 }\) and \(x _ { 4 }\), giving your answers to four decimal places.
      7
  4. (ii) On the graph below, draw a cobweb or staircase diagram to show how convergence takes place, indicating the positions of \(x _ { 2 } , x _ { 3 }\) and \(x _ { 4 }\).
    [0pt] [2 marks]
    \includegraphics[max width=\textwidth, alt={}, center]{6b1312f4-9a5c-4465-8129-7d37e99efefe-09_954_1600_1717_223}
AQA Paper 1 2019 June Q8
8 \(\quad \mathrm { P } ( n ) = \sum _ { k = 0 } ^ { n } k ^ { 3 } - \sum _ { k = 0 } ^ { n - 1 } k ^ { 3 }\) where \(n\) is a positive integer.
8
  1. Find \(\mathrm { P } ( 3 )\) and \(\mathrm { P } ( 10 )\)
    8
  2. Solve the equation \(\mathrm { P } ( n ) = 1.25 \times 10 ^ { 8 }\)
AQA Paper 1 2019 June Q9
9 Prove that the sum of a rational number and an irrational number is always irrational.
10
The volume of a spherical bubble is increasing at a constant rate.
Show that the rate of increase of the radius, \(r\), of the bubble is inversely proportional to \(r ^ { 2 }\) \(\text { Volume of a sphere } = \frac { 4 } { 3 } \pi r ^ { 3 }\)
\includegraphics[max width=\textwidth, alt={}]{6b1312f4-9a5c-4465-8129-7d37e99efefe-13_2488_1716_219_153}
Jodie is attempting to use differentiation from first principles to prove that the gradient of \(y = \sin x\) is zero when \(x = \frac { \pi } { 2 }\) Jodie's teacher tells her that she has made mistakes starting in Step 4 of her working. Her working is shown below.
\includegraphics[max width=\textwidth, alt={}, center]{6b1312f4-9a5c-4465-8129-7d37e99efefe-14_645_1298_584_370} Step 1 Gradient of chord \(A B = \frac { \sin \left( \frac { \pi } { 2 } + h \right) - \sin \left( \frac { \pi } { 2 } \right) } { h }\) Step 2 \(= \frac { \sin \left( \frac { \pi } { 2 } \right) \cos ( h ) + \cos \left( \frac { \pi } { 2 } \right) \sin ( h ) - \sin \left( \frac { \pi } { 2 } \right) } { h }\) Step 3 $$= \sin \left( \frac { \pi } { 2 } \right) \left( \frac { \cos ( h ) - 1 } { h } \right) + \cos \left( \frac { \pi } { 2 } \right) \frac { \sin ( h ) } { h }$$ Step 4
For gradient of curve at \(A\),
let \(h = 0\) then
\(\frac { \cos ( h ) - 1 } { h } = 0\) and \(\frac { \sin ( h ) } { h } = 0\)
Step 5
Hence the gradient of the curve at \(A\) is given by \(\sin \left( \frac { \pi } { 2 } \right) \times 0 + \cos \left( \frac { \pi } { 2 } \right) \times 0 = 0\) Complete Steps 4 and 5 of Jodie's working below, to correct her proof. Step 4 For gradient of curve at \(A\), Step 5 Hence the gradient of the curve at \(A\) is given by
AQA Paper 1 2019 June Q12
12
  1. Show that the equation $$2 \cot ^ { 2 } x + 2 \operatorname { cosec } ^ { 2 } x = 1 + 4 \operatorname { cosec } x$$ can be written in the form $$a \operatorname { cosec } ^ { 2 } x + b \operatorname { cosec } x + c = 0$$ 12
  2. Hence, given \(x\) is obtuse and $$2 \cot ^ { 2 } x + 2 \operatorname { cosec } ^ { 2 } x = 1 + 4 \operatorname { cosec } x$$ find the exact value of \(\tan x\) Fully justify your answer.
    13A curve, \(C\), has equation
    \(y = \frac { \mathrm { e } ^ { 3 x - 5 } } { x ^ { 2 } }\)
    Show that \(C\) has exactly one stationary point.
    Fully justify your answer.
    \includegraphics[max width=\textwidth, alt={}]{6b1312f4-9a5c-4465-8129-7d37e99efefe-19_2488_1716_219_153}
AQA Paper 1 2019 June Q14
1 marks
14 The graph of \(y = \frac { 2 x ^ { 3 } } { x ^ { 2 } + 1 }\) is shown for \(0 \leq x \leq 4\)
\includegraphics[max width=\textwidth, alt={}, center]{6b1312f4-9a5c-4465-8129-7d37e99efefe-20_1022_640_411_701} Caroline is attempting to approximate the shaded area, \(A\), under the curve using the trapezium rule by splitting the area into \(n\) trapezia. 14
  1. When \(n = 4\)
    14
    1. State the number of ordinates that Caroline uses. 14
  2. (ii) Calculate the area that Caroline should obtain using this method.
    Give your answer correct to two decimal places.
    14
  3. Show that the exact area of \(A\) is $$16 - \ln 17$$ Fully justify your answer.
    14
  4. Explain what would happen to Caroline's answer to part (a)(ii) as \(n \rightarrow \infty\)[1 mark]Do not write outside the box
    \includegraphics[max width=\textwidth, alt={}]{6b1312f4-9a5c-4465-8129-7d37e99efefe-23_2488_1716_219_153}