AQA Paper 1 2019 June — Question 9

Exam BoardAQA
ModulePaper 1 (Paper 1)
Year2019
SessionJune
TopicDifferentiation Applications
TypeRelated rates problems

9 Prove that the sum of a rational number and an irrational number is always irrational.
10
The volume of a spherical bubble is increasing at a constant rate.
Show that the rate of increase of the radius, \(r\), of the bubble is inversely proportional to \(r ^ { 2 }\) \(\text { Volume of a sphere } = \frac { 4 } { 3 } \pi r ^ { 3 }\)
\includegraphics[max width=\textwidth, alt={}]{6b1312f4-9a5c-4465-8129-7d37e99efefe-13_2488_1716_219_153}
Jodie is attempting to use differentiation from first principles to prove that the gradient of \(y = \sin x\) is zero when \(x = \frac { \pi } { 2 }\) Jodie's teacher tells her that she has made mistakes starting in Step 4 of her working. Her working is shown below.
\includegraphics[max width=\textwidth, alt={}, center]{6b1312f4-9a5c-4465-8129-7d37e99efefe-14_645_1298_584_370} Step 1 Gradient of chord \(A B = \frac { \sin \left( \frac { \pi } { 2 } + h \right) - \sin \left( \frac { \pi } { 2 } \right) } { h }\) Step 2 \(= \frac { \sin \left( \frac { \pi } { 2 } \right) \cos ( h ) + \cos \left( \frac { \pi } { 2 } \right) \sin ( h ) - \sin \left( \frac { \pi } { 2 } \right) } { h }\) Step 3 $$= \sin \left( \frac { \pi } { 2 } \right) \left( \frac { \cos ( h ) - 1 } { h } \right) + \cos \left( \frac { \pi } { 2 } \right) \frac { \sin ( h ) } { h }$$ Step 4
For gradient of curve at \(A\),
let \(h = 0\) then
\(\frac { \cos ( h ) - 1 } { h } = 0\) and \(\frac { \sin ( h ) } { h } = 0\)
Step 5
Hence the gradient of the curve at \(A\) is given by \(\sin \left( \frac { \pi } { 2 } \right) \times 0 + \cos \left( \frac { \pi } { 2 } \right) \times 0 = 0\) Complete Steps 4 and 5 of Jodie's working below, to correct her proof. Step 4 For gradient of curve at \(A\), Step 5 Hence the gradient of the curve at \(A\) is given by