8.
\begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{b3e54459-0d05-4858-8978-60fe3d4d1719-16_286_933_201_459}
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\caption{Figure 1}
\end{figure}
A smooth solid hemisphere is fixed with its flat surface in contact with rough horizontal ground. The hemisphere has centre \(O\) and radius \(5 a\).
A uniform rod \(A B\), of length \(16 a\) and weight \(W\), rests in equilibrium on the hemisphere with end \(A\) on the ground. The rod rests on the hemisphere at the point \(C\), where \(A C = 12 a\) and angle \(C A O = \alpha\), as shown in Figure 1.
Points \(A , C , B\) and \(O\) all lie in the same vertical plane.
- Explain why \(A O = 13 a\)
The normal reaction on the rod at \(C\) has magnitude \(k W\)
- Show that \(k = \frac { 8 } { 13 }\)
The resultant force acting on the rod at \(A\) has magnitude \(R\) and acts upwards at \(\theta ^ { \circ }\) to the horizontal.
- Find
- an expression for \(R\) in terms of \(W\)
- the value of \(\theta\)
(8)
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[Question 8 Continued]
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