SPS SPS FM Mechanics 2025 January — Question 5 13 marks

Exam BoardSPS
ModuleSPS FM Mechanics (SPS FM Mechanics)
Year2025
SessionJanuary
Marks13
TopicCentre of Mass 2
TypeContainer or open-topped solid
DifficultyChallenging +1.2 This is a standard Further Maths mechanics problem requiring systematic application of the centre of mass formula for composite bodies (subtraction method) and equilibrium of a suspended body. Part (a) involves careful bookkeeping with fractions but follows a routine procedure. Part (b) requires setting up moments about the suspension point using the given angle, which is a standard technique. The calculations are somewhat involved but the methods are well-practiced in FM mechanics courses with no novel insight required.
Spec6.04c Composite bodies: centre of mass6.04d Integration: for centre of mass of laminas/solids

5. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{7ecb33af-c165-4b72-98f2-7574fad3fdd5-10_881_1301_173_397} \captionsetup{labelformat=empty} \caption{Figure 3}
\end{figure} A uniform solid right circular cylinder has height \(h\) and radius \(r\). The centre of one plane face is \(O\) and the centre of the other plane face is \(Y\). A cylindrical hole is made by removing a solid cylinder of radius \(\frac { 1 } { 4 } r\) and height \(\frac { 1 } { 4 } h\) from the end with centre \(O\). The axis of the cylinder removed is parallel to \(O Y\) and meets the end with centre \(O\) at \(X\), where \(O X = \frac { 1 } { 4 } r\). One plane face of the cylinder removed coincides with the plane face through \(O\) of the original cylinder. The resulting solid \(S\) is shown in Figure 3.
  1. Show that the centre of mass of \(S\) is at a distance \(\frac { 85 h } { 168 }\) from the plane face
    containing \(O\). containing \(O\). The solid \(S\) is freely suspended from \(O\). In equilibrium the line \(O Y\) is inclined at an angle \(\arctan ( 17 )\) to the horizontal.
  2. Find \(r\) in terms of \(h\).
    [0pt] [Question 5 Continued]
    [0pt] [Question 5 Continued]

5.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{7ecb33af-c165-4b72-98f2-7574fad3fdd5-10_881_1301_173_397}
\captionsetup{labelformat=empty}
\caption{Figure 3}
\end{center}
\end{figure}

A uniform solid right circular cylinder has height $h$ and radius $r$. The centre of one plane face is $O$ and the centre of the other plane face is $Y$. A cylindrical hole is made by removing a solid cylinder of radius $\frac { 1 } { 4 } r$ and height $\frac { 1 } { 4 } h$ from the end with centre $O$. The axis of the cylinder removed is parallel to $O Y$ and meets the end with centre $O$ at $X$, where $O X = \frac { 1 } { 4 } r$. One plane face of the cylinder removed coincides with the plane face through $O$ of the original cylinder. The resulting solid $S$ is shown in Figure 3.
\begin{enumerate}[label=(\alph*)]
\item Show that the centre of mass of $S$ is at a distance $\frac { 85 h } { 168 }$ from the plane face\\
containing $O$. containing $O$.

The solid $S$ is freely suspended from $O$. In equilibrium the line $O Y$ is inclined at an angle $\arctan ( 17 )$ to the horizontal.
\item Find $r$ in terms of $h$.\\[0pt]
[Question 5 Continued]\\[0pt]
[Question 5 Continued]
\end{enumerate}

\hfill \mbox{\textit{SPS SPS FM Mechanics 2025 Q5 [13]}}