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A container in the shape of a cuboid has a square base of side \(x\) and a height of \((10 - x)\). It is given that \(x\) varies with time, \(t\), where \(t > 0\). The container decreases in volume at a rate which is inversely proportional to \(t\).
When \(t = \frac{1}{10}\), \(x = \frac{1}{2}\) and the rate of decrease of \(x\) is \(\frac{20}{37}\).
- Show that \(x\) and \(t\) satisfy the differential equation
$$\frac{dx}{dt} = \frac{-1}{2t(20x - 3x^2)}$$ [5]
- Solve the differential equation, obtaining an expression for \(t\) in terms of \(x\). [6]