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AQA S1 2015 June Q6
12 marks Moderate -0.8
6 Customers at a supermarket can pay at a checkout either by cash, debit card or credit card.
  1. The probability that a customer pays by cash is 0.22 . Calculate the probability that exactly 2 customers from a random sample of 24 customers pay by cash.
  2. The probability that a customer pays by debit card is 0.45 . Determine the probability that the number of customers who pay by debit card from a random sample of \(\mathbf { 4 0 }\) customers is:
    1. fewer than 20 ;
    2. more than 15 ;
    3. at least 12 but at most 24 .
  3. The random variable \(W\) denotes the number of customers who pay by credit card from a random sample of \(\mathbf { 2 0 0 }\) customers. Calculate values for the mean and the variance of \(W\).
    [0pt] [3 marks]
AQA S1 2015 June Q7
10 marks Moderate -0.3
7
  1. A greengrocer displays apples in trays. Each customer selects the apples he or she wishes to buy and puts them into a bag. Records show that the weight of such bags of apples may be modelled by a normal distribution with mean 1.16 kg and standard deviation 0.43 kg . Determine the probability that the mean weight of a random sample of 10 such bags of apples exceeds 1.25 kg .
  2. The greengrocer also displays pears in trays. Each customer selects the pears he or she wishes to buy and puts them into a bag. A random sample of 40 such bags of pears had a mean weight of 0.86 kg and a standard deviation of 0.65 kg .
    1. Construct a \(\mathbf { 9 6 \% }\) confidence interval for the mean weight of a bag of pears.
    2. Hence comment on a claim that customers wish to buy, on average, a greater weight of apples than of pears.
      [0pt] [2 marks]
AQA S1 2015 June Q1
4 marks Moderate -0.8
1
The table shows the annual gas consumption, \(x \mathrm { kWh }\), and the annual electricity consumption, \(y \mathrm { kWh }\), for a sample of 10 bungalows of similar size and occupancy.
\(\boldsymbol { x }\)21371185211522217312198542356120738221111789724523
\(\boldsymbol { y }\)2281232722212378278728563078264725662559
$$S _ { x x } = 76581640 \quad S _ { y y } = 694250 \quad S _ { x y } = 3629670$$
  1. Calculate the value of \(r _ { x y }\), the product moment correlation coefficient between \(x\) and \(y\).
  2. Interpret your value of \(r _ { x y }\) in the context of this question.
AQA S1 2015 June Q2
6 marks Easy -1.2
2 The table summarises the diameters, \(d\) millimetres, of a random sample of 60 new cricket balls to be used in junior cricket.
AQA S1 2015 June Q3
13 marks Moderate -0.8
3 A ferry sails once each day from port D to port A. The ferry departs from D on time or late but never early. However, the ferry can arrive at A early, on time or late. The probabilities for some combined events of departing from \(D\) and arriving at \(A\) are shown in the table below.
  1. Complete the table.
  2. Write down the probability that, on a particular day, the ferry:
    1. both departs and arrives on time;
    2. departs late.
  3. Find the probability that, on a particular day, the ferry:
    1. arrives late, given that it departed late;
    2. does not arrive late, given that it departed on time.
  4. On three particular days, the ferry departs from port D on time. Find the probability that, on these three days, the ferry arrives at port A early once, on time once and late once. Give your answer to three decimal places.
    [0pt] [4 marks]
    1. \begin{table}[h]
      \captionsetup{labelformat=empty} \caption{Answer space for question 3}
      \multirow{2}{*}{}Arrive at A
      EarlyOn timeLateTotal
      \multirow{2}{*}{Depart from D}On time0.160.560.08
      Late
      Total0.220.651.00
      \end{table}
AQA S1 2015 June Q4
15 marks Moderate -0.3
4 Stephan is a roofing contractor who is often required to replace loose ridge tiles on house roofs. In order to help him to quote more accurately the prices for such jobs in the future, he records, for each of 11 recently repaired roofs, the number of ridge tiles replaced, \(x _ { i }\), and the time taken, \(y _ { i }\) hours. His results are shown in the table.
Roof \(( \boldsymbol { i } )\)\(\mathbf { 1 }\)\(\mathbf { 2 }\)\(\mathbf { 3 }\)\(\mathbf { 4 }\)\(\mathbf { 5 }\)\(\mathbf { 6 }\)\(\mathbf { 7 }\)\(\mathbf { 8 }\)\(\mathbf { 9 }\)\(\mathbf { 1 0 }\)\(\mathbf { 1 1 }\)
\(\boldsymbol { x } _ { \boldsymbol { i } }\)811141416202222252730
\(\boldsymbol { y } _ { \boldsymbol { i } }\)5.05.26.37.28.08.810.611.011.812.113.0
  1. The pairs of data values for roofs 1 to 7 are plotted on the scatter diagram shown on the opposite page. Plot the 4 pairs of data values for roofs 8 to 11 on the scatter diagram.
    1. Calculate the equation of the least squares regression line of \(y _ { i }\) on \(x _ { i }\), and draw your line on the scatter diagram.
    2. Interpret your values for the gradient and for the intercept of this regression line.
  2. Estimate the time that it would take Stephan to replace 15 loose ridge tiles on a house roof.
  3. Given that \(r _ { i }\) denotes the residual for the point representing roof \(i\) :
    1. calculate the value of \(r _ { 6 }\);
    2. state why the value of \(\sum _ { i = 1 } ^ { 11 } r _ { i }\) gives no useful information about the connection between the number of ridge tiles replaced and the time taken.
      [0pt] [1 mark]
      \section*{Answer space for question 4}
      \includegraphics[max width=\textwidth, alt={}]{6fbb8891-e6de-42fe-a195-ea643552fdcf-11_2385_1714_322_155}
AQA S1 2015 June Q5
12 marks Moderate -0.3
5
  1. Wooden lawn edging is supplied in 1.8 m length rolls. The actual length, \(X\) metres, of a roll may be modelled by a normal distribution with mean 1.81 and standard deviation 0.08 . Determine the probability that a randomly selected roll has length:
    1. less than 1.90 m ;
    2. greater than 1.85 m ;
    3. between 1.81 m and 1.85 m .
  2. Plastic lawn edging is supplied in 9 m length rolls. The actual length, \(Y\) metres, of a roll may be modelled by a normal distribution with mean \(\mu\) and standard deviation \(\sigma\). An analysis of a batch of rolls, selected at random, showed that $$\mathrm { P } ( Y < 9.25 ) = 0.88$$
    1. Use this probability to find the value of \(z\) such that $$9.25 - \mu = z \times \sigma$$ where \(z\) is a value of \(Z \sim \mathrm {~N} ( 0,1 )\).
    2. Given also that $$\mathrm { P } ( Y > 8.75 ) = 0.975$$ find values for \(\mu\) and \(\sigma\).
AQA S1 2015 June Q6
13 marks Moderate -0.8
6
  1. In a particular country, 35 per cent of the population is estimated to have at least one mobile phone. A sample of 40 people is selected from the population.
    Use the distribution \(\mathrm { B } ( 40,0.35 )\) to estimate the probability that the number of people in the sample that have at least one mobile phone is:
    1. at most 15 ;
    2. more than 10 ;
    3. more than 12 but fewer than 18 ;
    4. exactly equal to the mean of the distribution.
  2. In the same country, 70 per cent of households have a landline telephone connection. A sample of 50 households is selected from all households in the country.
    Stating a necessary condition regarding this selection, estimate the probability that fewer than 30 households have a landline telephone connection.
    [0pt] [4 marks]
AQA S1 2015 June Q7
12 marks Moderate -0.3
7
  1. The weight of a sack of mixed dog biscuits can be modelled by a normal distribution with a mean of 10.15 kg and a standard deviation of 0.3 kg . A pet shop purchases 12 such sacks that can be considered to be a random sample.
    Calculate the probability that the mean weight of the 12 sacks is less than 10 kg .
  2. The weight of dry cat food in a pouch can also be modelled by a normal distribution. The contents, \(x\) grams, of each of a random sample of 40 pouches were weighed. Subsequent analysis of these weights gave $$\bar { x } = 304.6 \quad \text { and } \quad s = 5.37$$
    1. Construct a \(99 \%\) confidence interval for the mean weight of dry cat food in a pouch. Give the limits to one decimal place.
    2. Comment, with justification, on each of the following two claims. Claim 1: The mean weight of dry cat food in a pouch is more than 300 grams.
      Claim 2: All pouches contain more than 300 grams of dry cat food.
      [0pt] [4 marks]
      \includegraphics[max width=\textwidth, alt={}]{6fbb8891-e6de-42fe-a195-ea643552fdcf-24_2288_1705_221_155}
OCR S1 Q3
8 marks Moderate -0.8
3 In a supermarket the proportion of shoppers who buy washing powder is denoted by \(p\). 16 shoppers are selected at random.
  1. Given that \(p = 0.35\), use tables to find the probability that the number of shoppers who buy washing powder is
    1. at least 8,
    2. between 4 and 9 inclusive.
    3. Given instead that \(p = 0.38\), find the probability that the number of shoppers who buy washing powder is exactly 6 . \section*{June 2005}
OCR S1 Q4
8 marks Moderate -0.3
4 The table shows the latitude, \(x\) (in degrees correct to 3 significant figures), and the average rainfall \(y\) (in cm correct to 3 significant figures) of five European cities.
City\(x\)\(y\)
Berlin52.558.2
Bucharest44.458.7
Moscow55.853.3
St Petersburg60.047.8
Warsaw52.356.6
$$\left[ n = 5 , \Sigma x = 265.0 , \Sigma y = 274.6 , \Sigma x ^ { 2 } = 14176.54 , \Sigma y ^ { 2 } = 15162.22 , \Sigma x y = 14464.10 . \right]$$
  1. Calculate the product moment correlation coefficient.
  2. The values of \(y\) in the table were in fact obtained from measurements in inches and converted into centimetres by multiplying by 2.54. State what effect it would have had on the value of the product moment correlation coefficient if it had been calculated using inches instead of centimetres.
  3. It is required to estimate the annual rainfall at Bergen, where \(x = 60.4\). Calculate the equation of an appropriate line of regression, giving your answer in simplified form, and use it to find the required estimate. \section*{June 2005}
OCR S1 Q5
13 marks Moderate -0.8
5 The examination marks obtained by 1200 candidates are illustrated on the cumulative frequency graph, where the data points are joined by a smooth curve. \includegraphics[max width=\textwidth, alt={}, center]{11316ea6-3999-4003-b77d-bee8b547c1da-04_1335_1319_404_413} Use the curve to estimate
  1. the interquartile range of the marks,
  2. \(x\), if \(40 \%\) of the candidates scored more than \(x\) marks,
  3. the number of candidates who scored more than 68 marks. Five of the candidates are selected at random, with replacement.
  4. Estimate the probability that all five scored more than 68 marks. It is subsequently discovered that the candidates' marks in the range 35 to 55 were evenly distributed - that is, roughly equal numbers of candidates scored \(35,36,37 , \ldots , 55\).
  5. What does this information suggest about the estimate of the interquartile range found in part (i)? \section*{June 2005}
OCR S1 Q6
13 marks Standard +0.3
6 Two bags contain coloured discs. At first, bag \(P\) contains 2 red discs and 2 green discs, and bag \(Q\) contains 3 red discs and 1 green disc. A disc is chosen at random from bag \(P\), its colour is noted and it is placed in bag \(Q\). A disc is then chosen at random from bag \(Q\), its colour is noted and it is placed in bag \(P\). A disc is then chosen at random from bag \(P\). The tree diagram shows the different combinations of three coloured discs chosen. \includegraphics[max width=\textwidth, alt={}, center]{11316ea6-3999-4003-b77d-bee8b547c1da-05_858_980_573_585}
  1. Write down the values of \(a , b , c , d , e\) and \(f\). The total number of red discs chosen, out of 3, is denoted by \(R\). The table shows the probability distribution of \(R\).
    \(r\)0123
    \(\mathrm { P } ( R = r )\)\(\frac { 1 } { 10 }\)\(k\)\(\frac { 9 } { 20 }\)\(\frac { 1 } { 5 }\)
  2. Show how to obtain the value \(\mathrm { P } ( R = 2 ) = \frac { 9 } { 20 }\).
  3. Find the value of \(k\).
  4. Calculate the mean and variance of \(R\).
OCR S1 Q7
14 marks Moderate -0.3
7 A committee of 7 people is to be chosen at random from 18 volunteers.
  1. In how many different ways can the committee be chosen? The 18 volunteers consist of 5 people from Gloucester, 6 from Hereford and 7 from Worcester. The committee is to be chosen randomly. Find the probability that the committee will
  2. consist of 2 people from Gloucester, 2 people from Hereford and 3 people from Worcester,
  3. include exactly 5 people from Worcester,
  4. include at least 2 people from each of the three cities. 1 Jenny and John are each allowed two attempts to pass an examination.
  1. Jenny estimates that her chances of success are as follows.
    Calculate the probability that if John fails on his first attempt, he will pass on his second attempt. 2 For each of 50 plants, the height, \(h \mathrm {~cm}\), was measured and the value of ( \(h - 100\) ) was recorded. The mean and standard deviation of \(( h - 100 )\) were found to be 24.5 and 4.8 respectively.
  1. Write down the mean and standard deviation of \(h\). The mean and standard deviation of the heights of another 100 plants were found to be 123.0 cm and 5.1 cm respectively.
  2. Describe briefly how the heights of the second group of plants compare with the first.
  3. Calculate the mean height of all 150 plants. 3 In Mr Kendall's cupboard there are 3 tins of baked beans and 2 tins of pineapple. Unfortunately his daughter has removed all the labels for a school project and so the tins are identical in appearance. Mr Kendall wishes to use both tins of pineapple for a fruit salad. He opens tins at random until he has opened the two tins of pineapples. Let \(X\) be the number of tins that Mr Kendall opens.
  1. Show that \(\mathrm { P } ( X = 3 ) = \frac { 1 } { 5 }\).
  2. The probability distribution of \(X\) is given in the table below.
    \(x\)2345
    \(\mathrm { P } ( X = x )\)\(\frac { 1 } { 10 }\)\(\frac { 1 } { 5 }\)\(\frac { 3 } { 10 }\)\(\frac { 2 } { 5 }\)
    Find \(\mathrm { E } ( X )\) and \(\operatorname { Var } ( X )\).
OCR S1 Q8
13 marks Moderate -0.3
8 The table shows the population, \(x\) million, of each of nine countries in Western Europe together with the population, \(y\) million, of its capital city.
GermanyUnited KingdomFranceItalySpainThe NetherlandsPortugalAustriaSwitzerland
\(x\)82.159.259.156.739.215.99.98.17.3
\(y\)3.57.09.02.72.90.80.71.60.1
$$\left[ n = 9 , \Sigma x = 337.5 , \Sigma x ^ { 2 } = 18959.11 , \Sigma y = 28.3 , \Sigma y ^ { 2 } = 161.65 , \Sigma x y = 1533.76 . \right]$$
  1. (a) Calculate Spearman's rank correlation coefficient, \(r _ { s }\).
    (b) Explain what your answer indicates about the populations of these countries and their capital cities.
  2. Calculate the product moment correlation coefficient, \(r\). The data are illustrated in the scatter diagram. \includegraphics[max width=\textwidth, alt={}, center]{11316ea6-3999-4003-b77d-bee8b547c1da-09_936_881_1162_632}
  3. By considering the diagram, state the effect on the value of the product moment correlation coefficient, \(r\), if the data for France and the United Kingdom were removed from the calculation.
  4. In a certain country in Africa, most people live in remote areas and hence the population of the country is unknown. However, the population of the capital city is known to be approximately 1 million. An official suggests that the population of this country could be estimated by using a regression line drawn on the above scatter diagram.
    (a) State, with a reason, whether the regression line of \(y\) on \(x\) or the regression line of \(x\) on \(y\) would need to be used.
    (b) Comment on the reliability of such an estimate in this situation. 1 Some observations of bivariate data were made and the equations of the two regression lines were found to be as follows. $$\begin{array} { c c } y \text { on } x : & y = - 0.6 x + 13.0 \\ x \text { on } y : & x = - 1.6 y + 21.0 \end{array}$$
  1. State, with a reason, whether the correlation between \(x\) and \(y\) is negative or positive.
  2. Neither variable is controlled. Calculate an estimate of the value of \(x\) when \(y = 7.0\).
  3. Find the values of \(\bar { x }\) and \(\bar { y }\). 2 A bag contains 5 black discs and 3 red discs. A disc is selected at random from the bag. If it is red it is replaced in the bag. If it is black, it is not replaced. A second disc is now selected at random from the bag. Find the probability that
  1. the second disc is black, given that the first disc was black,
  2. the second disc is black,
  3. the two discs are of different colours. 3 Each of the 7 letters in the word DIVIDED is printed on a separate card. The cards are arranged in a row.
  1. How many different arrangements of the letters are possible?
  2. In how many of these arrangements are all three Ds together? The 7 cards are now shuffled and 2 cards are selected at random, without replacement.
  3. Find the probability that at least one of these 2 cards has D printed on it.
4
  1. The random variable \(X\) has the distribution \(\mathrm { B } ( 25,0.2 )\). Using the tables of cumulative binomial probabilities, or otherwise, find \(\mathrm { P } ( X \geqslant 5 )\).
  2. The random variable \(Y\) has the distribution \(\mathrm { B } ( 10,0.27 )\). Find \(\mathrm { P } ( Y = 3 )\).
  3. The random variable \(Z\) has the distribution \(B ( n , 0.27 )\). Find the smallest value of \(n\) such that \(\mathrm { P } ( Z \geqslant 1 ) > 0.95\). 5 The probability distribution of a discrete random variable, \(X\), is given in the table.
    \(x\)0123
    \(\mathrm { P } ( X = x )\)\(\frac { 1 } { 3 }\)\(\frac { 1 } { 4 }\)\(p\)\(q\)
    It is given that the expectation, \(\mathrm { E } ( X )\), is \(1 \frac { 1 } { 4 }\).
  1. Calculate the values of \(p\) and \(q\).
  2. Calculate the standard deviation of \(X\).
AQA S2 2009 January Q1
11 marks Standard +0.3
1 Fortune High School gave its students a wider choice of subjects to study. The table shows the number of students, of each gender, who chose to study each of the additional subjects during the school year 2007/08.
\cline { 2 - 5 } \multicolumn{1}{c|}{}Bulgarian
Climate
Change
FinancePolish
Male7312540
Female2242219
Assuming that these data form a random sample, use a \(\chi ^ { 2 }\) test, at the \(10 \%\) level of significance, to test whether the choice of these subjects is independent of gender.
(11 marks)
AQA S2 2009 January Q2
9 marks Standard +0.3
2 A group of estate agents in a particular area claimed that, after the introduction of a new search procedure at the Land Registry, the mean completion time for the purchase of a house in the area had not changed from 8 weeks.
  1. A random sample of 9 house purchases in the area revealed that their completion times, in weeks, were as follows. $$\begin{array} { l l l l l l l l l } 6 & 7 & 10 & 12 & 9 & 11 & 7 & 8 & 14 \end{array}$$ Assuming that completion times in the area are normally distributed with standard deviation 2.5 weeks, test, at the \(5 \%\) level of significance, the group's claim. (7 marks)
  2. It was subsequently discovered that, after the introduction of the new search procedure at the Land Registry, the mean completion time for the purchase of a house in the area remained at 8 weeks. Indicate whether a Type I error, a Type II error or neither has occurred in carrying out your hypothesis test in part (a). Give a reason for your answer.
    (2 marks)
AQA S2 2009 January Q3
14 marks Moderate -0.3
3 Joe owns two garages, Acefit and Bestjob, each specialising in the fitting of the latest satellite navigation device. The daily demand, \(X\), for the device at Acefit garage may be modelled by a Poisson distribution with mean 3.6. The daily demand, \(Y\), for the device at Bestjob garage may be modelled by a Poisson distribution with mean 4.4.
  1. Calculate:
    1. \(\mathrm { P } ( X \leqslant 3 )\);
    2. \(\quad \mathrm { P } ( Y = 5 )\).
  2. The total daily demand for the device at Joe's two garages is denoted by \(T\).
    1. Write down the distribution of \(T\), stating any assumption that you make.
    2. Determine \(\mathrm { P } ( 6 < T < 12 )\).
    3. Calculate the probability that the total demand for the device will exceed 14 on each of two consecutive days. Give your answer to one significant figure.
    4. Determine the minimum number of devices that Joe should have in stock if he is to meet his total demand on at least \(99 \%\) of days.
AQA S2 2009 January Q4
6 marks Moderate -0.3
4 The continuous random variable \(X\) has the cumulative distribution function $$\mathrm { F } ( x ) = \left\{ \begin{array} { c c } 0 & x < - c \\ \frac { x + c } { 4 c } & - c \leqslant x \leqslant 3 c \\ 1 & x > 3 c \end{array} \right.$$ where \(c\) is a positive constant.
  1. Determine \(\mathrm { P } \left( - \frac { 3 c } { 4 } < X < \frac { 3 c } { 4 } \right)\).
  2. Show that the probability density function, \(\mathrm { f } ( x )\), of \(X\) is $$f ( x ) = \left\{ \begin{array} { c c } \frac { 1 } { 4 c } & - c \leqslant x \leqslant 3 c \\ 0 & \text { otherwise } \end{array} \right.$$
  3. Hence, or otherwise, find expressions, in terms of \(c\), for:
    1. \(\mathrm { E } ( X )\);
    2. \(\operatorname { Var } ( X )\).
AQA S2 2009 January Q5
13 marks Standard +0.3
5 Jane, who supplies fruit to a jam manufacturer, knows that the weight of fruit in boxes that she sends to the manufacturer can be modelled by a normal distribution with unknown mean, \(\mu\) grams, and unknown standard deviation, \(\sigma\) grams. Jane selects a random sample of 16 boxes and, using the \(t\)-distribution, calculates correctly that a \(98 \%\) confidence interval for \(\mu\) is \(( 70.65,80.35 )\).
    1. Show that the sample mean is 75.5 grams.
    2. Find the width of the confidence interval.
    3. Calculate an estimate of the standard error of the mean.
    4. Hence, or otherwise, show that an unbiased estimate of \(\sigma ^ { 2 }\) is 55.6 , correct to three significant figures.
  1. Jane decides that the width of the \(98 \%\) confidence interval is too large. Construct a \(95 \%\) confidence interval for \(\mu\), based on her sample of 16 boxes.
  2. Jane is informed that the manufacturer would prefer the confidence interval to have a width of at most 5 grams.
    1. Write down a confidence interval for \(\mu\), again based on Jane's sample of 16 boxes, which has a width of 5 grams.
    2. Determine the percentage confidence level for your interval in part (c)(i).
AQA S2 2009 January Q6
10 marks Standard +0.3
6 A small supermarket has a total of four checkouts, at least one of which is always staffed. The probability distribution for \(R\), the number of checkouts that are staffed at any given time, is $$\mathrm { P } ( R = r ) = \left\{ \begin{array} { c l } \frac { 2 } { 3 } \left( \frac { 1 } { 3 } \right) ^ { r - 1 } & r = 1,2,3 \\ k & r = 4 \end{array} \right.$$
  1. Show that \(k = \frac { 1 } { 27 }\).
  2. Find the probability that, at any given time, there will be at least 3 checkouts that are staffed.
  3. It is suggested that the total number of customers, \(C\), that can be served at the checkouts per hour may be modelled by $$C = 27 R + 5$$ Find:
    1. \(\mathrm { E } ( C )\);
    2. the standard deviation of \(C\).
AQA S2 2009 January Q7
12 marks Standard +0.3
7 The continuous random variable \(X\) has the probability density function given by $$f ( x ) = \left\{ \begin{array} { c c } \frac { 1 } { 16 } x ^ { 3 } & 0 \leqslant x \leqslant 2 \\ \frac { 1 } { 6 } ( 5 - x ) & 2 \leqslant x \leqslant 5 \\ 0 & \text { otherwise } \end{array} \right.$$
  1. Sketch the graph of f.
  2. Prove that the cumulative distribution function of \(X\) for \(2 \leqslant x \leqslant 5\) can be written in the form $$\mathrm { F } ( x ) = 1 - \frac { 1 } { 12 } ( 5 - x ) ^ { 2 }$$
  3. Hence, or otherwise, determine \(\mathrm { P } ( X \geqslant 3 \mid X \leqslant 4 )\).
AQA S2 2007 June Q1
10 marks Standard +0.3
1 Two groups of patients, suffering from the same medical condition, took part in a clinical trial of a new drug. One of the groups was given the drug whilst the other group was given a placebo, a drug that has no physical effect on their medical condition. The table shows the number of patients in each group and whether or not their condition improved.
\cline { 2 - 3 } \multicolumn{1}{c|}{}PlaceboDrug
Condition improved2046
Condition did not improve5529
Conduct a \(\chi ^ { 2 }\) test, at the \(5 \%\) level of significance, to determine whether the condition of the patients at the conclusion of the trial is associated with the treatment that they were given.
(10 marks)
AQA S2 2007 June Q2
10 marks Moderate -0.8
2 The number of telephone calls per day, \(X\), received by Candice may be modelled by a Poisson distribution with mean 3.5. The number of e-mails per day, \(Y\), received by Candice may be modelled by a Poisson distribution with mean 6.0.
  1. For any particular day, find:
    1. \(\mathrm { P } ( X = 3 )\);
    2. \(\quad \mathrm { P } ( Y \geqslant 5 )\).
    1. Write down the distribution of \(T\), the total number of telephone calls and e-mails per day received by Candice.
    2. Determine \(\mathrm { P } ( 7 \leqslant T \leqslant 10 )\).
    3. Hence calculate the probability that, on each of three consecutive days, Candice will receive a total of at least 7 but at most 10 telephone calls and e-mails.
      (2 marks)
AQA S2 2007 June Q3
8 marks Standard +0.3
3 David is the professional coach at the golf club where Becki is a member. He claims that, after having a series of lessons with him, the mean number of putts that Becki takes per round of golf will reduce from her present mean of 36 . After having the series of lessons with David, Becki decides to investigate his claim.
She therefore records, for each of a random sample of 50 rounds of golf, the number of putts, \(x\), that she takes to complete the round. Her results are summarised below, where \(\bar { x }\) denotes the sample mean. $$\sum x = 1730 \quad \text { and } \quad \sum ( x - \bar { x } ) ^ { 2 } = 784$$ Using a \(z\)-test and the \(1 \%\) level of significance, investigate David's claim.