\includegraphics{figure_4}
\(ABCDEF\) is the cross-section through the centre of mass of a uniform solid prism. \(ABCF\) is a rectangle in which \(AB = CF = 1.6\) m, and \(BC = AF = 0.4\) m. \(CDE\) is a triangle in which \(CD = 1.8\) m, \(CE = 0.4\) m, and angle \(DCE = 90°\). The prism stands on a rough horizontal surface. A horizontal force of magnitude \(T\) N acts at \(B\) in the direction \(CB\) (see diagram). The prism is in equilibrium.
- Show that the distance of the centre of mass of the prism from \(AB\) is \(0.488\) m. [4]
- Given that the weight of the prism is \(100\) N, find the greatest and least possible values of \(T\). [3]