The speed, \(v\) m s⁻¹, of a train at time \(t\) seconds is given by
\(v = \sqrt{(1.2^t - 1)}, \quad 0 \leq t \leq 30.\)
The following table shows the speed of the train at 5 second intervals.
| \(t\) | 0 | 5 | 10 | 15 | 20 | 25 | 30 |
| \(v\) | 0 | 1.22 | 2.28 | | 6.11 | | |
- Complete the table, giving the values of \(v\) to 2 decimal places.
[3]
The distance, \(s\) metres, travelled by the train in 30 seconds is given by
$$s = \int_0^{30} \sqrt{(1.2^t - 1)} \, dt.$$
- Use the trapezium rule, with all the values from your table, to estimate the value of \(s\).
[3]