The curve \(y = x^3\) intersects the line \(y = kx\), \(k > 0\), at the origin and the point \(P\). The region bounded by the curve and the line, between the origin and \(P\), is denoted by \(R\).
- Show that the area of the region \(R\) is \(\frac{1}{6}k^3\). [3]
The line \(x = a\) cuts the region \(R\) into two parts of equal area.
- Show that \(k^3 - 6a^2k + 4a^3 = 0\). [3]
The gradient of the line \(y = kx\) increases at a constant rate with respect to time \(t\). Given that \(\frac{dk}{dt} = 2\),
- determine the value of \(\frac{da}{dt}\) when \(a = 1\) and \(k = 2\), [4]
- determine the value of \(\frac{da}{dt}\) when \(a = 1\) and \(k = 2\), expressing your answer in the form \(p + q\sqrt{3}\), where \(p\) and \(q\) are integers. [5]