A group \(G\), of order 8, is generated by the elements \(a\), \(b\), \(c\). \(G\) has the properties
$$a^2 = b^2 = c^2 = e, \quad ab = ba, \quad bc = cb, \quad ca = ac,$$
where \(e\) is the identity.
- Using these properties and basic group properties as necessary, prove that \(abc = cba\). [2]
The operation table for \(G\) is shown below.
| \(e\) | \(a\) | \(b\) | \(c\) | \(bc\) | \(ca\) | \(ab\) | \(abc\) |
| \(e\) | \(e\) | \(a\) | \(b\) | \(c\) | \(bc\) | \(ca\) | \(ab\) | \(abc\) |
| \(a\) | \(a\) | \(e\) | \(ab\) | \(ca\) | \(abc\) | \(c\) | \(b\) | \(bc\) |
| \(b\) | \(b\) | \(ab\) | \(e\) | \(bc\) | \(c\) | \(abc\) | \(a\) | \(ca\) |
| \(c\) | \(c\) | \(ca\) | \(bc\) | \(e\) | \(b\) | \(a\) | \(abc\) | \(ab\) |
| \(bc\) | \(bc\) | \(abc\) | \(c\) | \(b\) | \(e\) | \(ab\) | \(ca\) | \(a\) |
| \(ca\) | \(ca\) | \(c\) | \(abc\) | \(a\) | \(ab\) | \(e\) | \(bc\) | \(b\) |
| \(ab\) | \(ab\) | \(b\) | \(a\) | \(abc\) | \(ca\) | \(bc\) | \(e\) | \(c\) |
| \(abc\) | \(abc\) | \(bc\) | \(ca\) | \(ab\) | \(a\) | \(b\) | \(c\) | \(e\) |
- List all the subgroups of order 2. [2]
- List five subgroups of order 4. [3]
- Determine whether all the subgroups of \(G\) which are of order 4 are isomorphic. [2]