A particle is projected from a point \(O\) with speed \(u\) at an angle of elevation \(\alpha\) above the horizontal and moves freely under gravity. When the particle has moved a horizontal distance \(x\), its height above \(O\) is \(y\).
- Show that
$$y = x \tan \alpha - \frac{gx^2}{2u^2 \cos^2 \alpha}$$ [4]
A girl throws a ball from a point \(A\) at the top of a cliff. The point \(A\) is 8 m above a horizontal beach. The ball is projected with speed 7 m s\(^{-1}\) at an angle of elevation of 45°. By modelling the ball as a particle moving freely under gravity,
- find the horizontal distance of the ball from \(A\) when the ball is 1 m above the beach. [5]
A boy is standing on the beach at the point \(B\) vertically below \(A\). He starts to run in a straight line with speed \(v\) m s\(^{-1}\), leaving \(B\) 0.4 seconds after the ball is thrown.
He catches the ball when it is 1 m above the beach.
- Find the value of \(v\). [4]