Two heavy boxes, \(M\) and \(N\), are connected securely by a length of rope.
The mass of \(M\) is 50 kilograms.
The mass of \(N\) is 80 kilograms.
\(M\) is placed near the bottom of a rough slope.
The slope is inclined at 60° above the horizontal.
The rope is passed over a smooth pulley at the top end of the slope so that \(N\) hangs with the rope vertical.
The boxes are initially held in this position, with the rope taut and running parallel to the line of greatest slope, as shown in the diagram below.
\includegraphics{figure_21}
When the boxes are released, \(M\) moves up the slope as \(N\) descends, with acceleration \(a\) m s\(^{-2}\)
The tension in the rope is \(T\) newtons.
- Explain why the equation of motion for \(N\) is
$$80g - T = 80a$$
[1 mark]
- Show that the normal reaction force between \(M\) and the slope is \(25g\) newtons.
[1 mark]
- The coefficient of friction, \(\mu\), between the slope and \(M\) is such that \(0 \leq \mu \leq 1\)
Show that
$$a \geq \frac{(11 - 5\sqrt{3})g}{26}$$
[6 marks]
- State one modelling assumption you have made throughout this question.
[1 mark]