8. ABCD is a parallelogram and ADM is a straight line.
\includegraphics[max width=\textwidth, alt={}, center]{b063f4ea-372b-4193-b8fe-a9f8017d7349-16_497_1102_278_294} \section*{Diagram NOT accurately drawn} \(\overrightarrow { A B } = a \quad \overrightarrow { B C } = b \quad \overrightarrow { D M } = \frac { 1 } { 2 } b\)
K is the point on AB such that \(\mathrm { AK } : \mathrm { AB } = \lambda : 1\)
L is the point on CD such that \(\mathrm { CL } : \mathrm { CD } = \mu : 1\)
KLM is a straight line.
Give that \(\lambda : \mu = 1 : 2\) use a vector method to find the value of \(\lambda\) and the value of \(\mu\).