SPS SPS SM Pure 2024 June — Question 13 4 marks

Exam BoardSPS
ModuleSPS SM Pure (SPS SM Pure)
Year2024
SessionJune
Marks4
TopicCircles
TypeCircle from diameter endpoints
DifficultyModerate -0.3 This is a straightforward application of the diameter property (angle in semicircle = 90°) requiring students to use perpendicular gradients. The setup is clear, requiring calculation of two gradients and solving a simple equation. While it involves multiple steps, each is routine and the problem type is standard in circle geometry, making it slightly easier than average.
Spec1.03d Circles: equation (x-a)^2+(y-b)^2=r^21.03f Circle properties: angles, chords, tangents

13. The point \(P ( p , 0 )\), the point \(Q ( - 2,10 )\) and the point \(R ( 8 , - 14 )\) lie on a circle, \(C _ { 2 }\) Given that
  • \(p\) is a positive constant
  • \(Q R\) is a diameter of \(C _ { 2 }\) find the exact value of \(p\).
    (4)
    (Total for Question 13 is 4 marks)

13. The point $P ( p , 0 )$, the point $Q ( - 2,10 )$ and the point $R ( 8 , - 14 )$ lie on a circle, $C _ { 2 }$

Given that

\begin{itemize}
  \item $p$ is a positive constant
  \item $Q R$ is a diameter of $C _ { 2 }$\\
find the exact value of $p$.\\
(4)\\
(Total for Question 13 is 4 marks)
\end{itemize}

\hfill \mbox{\textit{SPS SPS SM Pure 2024 Q13 [4]}}