SPS SPS SM Pure 2024 June — Question 15 5 marks

Exam BoardSPS
ModuleSPS SM Pure (SPS SM Pure)
Year2024
SessionJune
Marks5
TopicAreas by integration
TypeTrapezium rule estimation
DifficultyStandard +0.3 This is a straightforward two-part question combining trapezium rule (routine A-level technique) with finding area between curves. Part (a) is mechanical application of a formula, part (b) requires subtracting one integral from another and calculating a percentage. The calculus in part (b) is simple (integrating a quadratic), and the question clearly guides students through the steps. Slightly easier than average due to its structured nature and standard techniques.
Spec1.08e Area between curve and x-axis: using definite integrals1.09f Trapezium rule: numerical integration

15. In this question you must show detailed reasoning.
Solutions relying entirely on calculator technology are not acceptable.
The curve \(C _ { 1 }\) has equation \(y = \mathrm { f } ( x )\).
A table of values of \(x\) and \(y\) for \(y = \mathrm { f } ( x )\) is shown below, with the \(y\) values rounded to 4 decimal places where appropriate.
\(x\)00.511.52
\(y\)32.68332.42.14661.92
  1. Use the trapezium rule with all the values of \(y\) in the table to find an approximation for $$\int _ { 0 } ^ { 2 } f ( x ) d x$$ giving your answer to 3 decimal places.
    (2) \begin{figure}[h]
    \includegraphics[alt={},max width=\textwidth]{b063f4ea-372b-4193-b8fe-a9f8017d7349-30_627_581_1142_404} \captionsetup{labelformat=empty} \caption{Figure 1}
    \end{figure} \begin{figure}[h]
    \includegraphics[alt={},max width=\textwidth]{b063f4ea-372b-4193-b8fe-a9f8017d7349-30_524_442_1238_1183} \captionsetup{labelformat=empty} \caption{Figure 2}
    \end{figure} The region \(R\), shown shaded in Figure 1, is bounded by
    The region \(R\) forms part of the design for a logo shown in Figure 2.
    The design consists of the shaded region \(R\) inside a rectangle of width 2 and height 3
    Using calculus and the answer to part (a),
  2. calculate an estimate for the percentage of the logo which is shaded.

15.

In this question you must show detailed reasoning.\\
Solutions relying entirely on calculator technology are not acceptable.\\
The curve $C _ { 1 }$ has equation $y = \mathrm { f } ( x )$.\\
A table of values of $x$ and $y$ for $y = \mathrm { f } ( x )$ is shown below, with the $y$ values rounded to 4 decimal places where appropriate.

\begin{center}
\begin{tabular}{ | c | c | c | c | c | c | }
\hline
$x$ & 0 & 0.5 & 1 & 1.5 & 2 \\
\hline
$y$ & 3 & 2.6833 & 2.4 & 2.1466 & 1.92 \\
\hline
\end{tabular}
\end{center}
\begin{enumerate}[label=(\alph*)]
\item Use the trapezium rule with all the values of $y$ in the table to find an approximation for

$$\int _ { 0 } ^ { 2 } f ( x ) d x$$

giving your answer to 3 decimal places.\\
(2)

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{b063f4ea-372b-4193-b8fe-a9f8017d7349-30_627_581_1142_404}
\captionsetup{labelformat=empty}
\caption{Figure 1}
\end{center}
\end{figure}

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{b063f4ea-372b-4193-b8fe-a9f8017d7349-30_524_442_1238_1183}
\captionsetup{labelformat=empty}
\caption{Figure 2}
\end{center}
\end{figure}

The region $R$, shown shaded in Figure 1, is bounded by

\begin{itemize}
  \item the curve $C _ { 1 }$
  \item the curve $C _ { 2 }$ with equation $y = 2 - \frac { 1 } { 4 } x ^ { 2 }$
  \item the line with equation $x = 2$
  \item the $y$-axis
\end{itemize}

The region $R$ forms part of the design for a logo shown in Figure 2.\\
The design consists of the shaded region $R$ inside a rectangle of width 2 and height 3\\
Using calculus and the answer to part (a),
\item calculate an estimate for the percentage of the logo which is shaded.
\end{enumerate}

\hfill \mbox{\textit{SPS SPS SM Pure 2024 Q15 [5]}}