SPS SPS SM Pure 2024 June — Question 10 6 marks

Exam BoardSPS
ModuleSPS SM Pure (SPS SM Pure)
Year2024
SessionJune
Marks6
TopicProof
TypeContradiction proof about integers
DifficultyStandard +0.3 This is a straightforward proof question testing standard techniques (contradiction, counter-example, exhaustion) with relatively simple algebra. Part (a) factors to (x-y)(x+y)=1 requiring minimal insight, part (b) needs only one example like logâ‚‚4, and part (c) involves routine case-checking of n mod 2. These are textbook-level proof exercises slightly easier than average A-level questions.
Spec1.01a Proof: structure of mathematical proof and logical steps1.01c Disproof by counter example1.01d Proof by contradiction

  1. a) Use proof by contradiction to prove that there are no positive integers, \(x\) and \(y\), such that
$$x ^ { 2 } - y ^ { 2 } = 1$$ b) Prove, by counter-example, that the statement \section*{" if \(a\) is rational and \(b\) is irrational then \(\log _ { a } b\) is irrational"} is false.
c) Use algebra to prove by exhaustion that for all \(n \in \mathbb { N }\) $$\text { " } n ^ { 2 } - 2 \text { is not a multiple of } 4 "$$ \section*{(Total for Question 10 is 6 marks)}

\begin{enumerate}
  \item a) Use proof by contradiction to prove that there are no positive integers, $x$ and $y$, such that
\end{enumerate}

$$x ^ { 2 } - y ^ { 2 } = 1$$

b) Prove, by counter-example, that the statement

\section*{" if $a$ is rational and $b$ is irrational then $\log _ { a } b$ is irrational"}
is false.\\
c) Use algebra to prove by exhaustion that for all $n \in \mathbb { N }$

$$\text { " } n ^ { 2 } - 2 \text { is not a multiple of } 4 "$$

\section*{(Total for Question 10 is 6 marks)}

\hfill \mbox{\textit{SPS SPS SM Pure 2024 Q10 [6]}}