SPS SPS SM Pure 2024 June — Question 7 6 marks

Exam BoardSPS
ModuleSPS SM Pure (SPS SM Pure)
Year2024
SessionJune
Marks6
TopicLaws of Logarithms
TypeTwo unrelated log parts: one non-log algebraic part
DifficultyStandard +0.3 Part (i) is a straightforward logarithm equation requiring basic log laws and solving a linear equation. Part (ii) requires recognizing summation notation, applying log laws (log(y^r) = r·log(y)), and solving a quadratic, but the steps are mechanical once set up. This is slightly easier than average as it's primarily procedural with no novel insight required.
Spec1.06f Laws of logarithms: addition, subtraction, power rules4.06b Method of differences: telescoping series

  1. (i) Using the laws of logarithms, solve
$$\log _ { 3 } ( 4 x ) + 2 = \log _ { 3 } ( 5 x + 7 )$$ (ii) Given that $$\sum _ { r = 1 } ^ { 2 } \log _ { a } \left( y ^ { r } \right) = \sum _ { r = 1 } ^ { 2 } \left( \log _ { a } ( y ) \right) ^ { r } \quad y > 1 , a > 1 , y \neq a$$ find \(y\) in terms of \(a\), giving your answer in simplest form.
(3)

\begin{enumerate}
  \item (i) Using the laws of logarithms, solve
\end{enumerate}

$$\log _ { 3 } ( 4 x ) + 2 = \log _ { 3 } ( 5 x + 7 )$$

(ii) Given that

$$\sum _ { r = 1 } ^ { 2 } \log _ { a } \left( y ^ { r } \right) = \sum _ { r = 1 } ^ { 2 } \left( \log _ { a } ( y ) \right) ^ { r } \quad y > 1 , a > 1 , y \neq a$$

find $y$ in terms of $a$, giving your answer in simplest form.\\
(3)\\

\hfill \mbox{\textit{SPS SPS SM Pure 2024 Q7 [6]}}