OCR MEI Further Mechanics Major 2021 November — Question 3 4 marks

Exam BoardOCR MEI
ModuleFurther Mechanics Major (Further Mechanics Major)
Year2021
SessionNovember
Marks4
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Mark schemeDownload PDF ↗
TopicHooke's law and elastic energy
TypeElastic string equilibrium and statics
DifficultyModerate -0.8 Part (a) is a direct application of Hooke's law in equilibrium (T = λx/l, with T = mg), requiring only substitution of given values. Part (b) tests conceptual understanding that the elastic limit may be exceeded, but requires no calculation. This is a straightforward two-part question with minimal problem-solving demand, easier than average A-level mechanics.
Spec6.02g Hooke's law: T = k*x or T = lambda*x/l

3 One end of a light elastic spring of natural length 0.3 m is attached to a fixed point. A mass of 4 kg is attached to the other end of the spring. When the spring hangs vertically in equilibrium the extension of the spring is 0.02 m .
  1. Determine the modulus of elasticity of the spring. A student calculates that if the mass of 4 kg is removed and replaced with a mass of 20 kg the extension of the spring will be 0.1 m .
  2. Suggest a reason why this extension may not be 0.1 m .

Question 3:
AnswerMarks Guidance
3(a) T = 4g
λ (0.02)
= 4g
0.3
AnswerMarks
λ = 588(N)B1
M1
A1
AnswerMarks
[3]1.1
3.3
AnswerMarks
1.1Resolve vertically (possibly implied by
subsequent working)
Use of Hooke’s law with their 4g
cao oe e.g. 60g
AnswerMarks Guidance
3(b) e.g. spring stretched beyond its elastic limit
e.g. Hooke’s law no longer appliesB1
[1]2.2b oe (any correct equivalent statement for
why the extension of the spring may not
be 0.1 m)
Question 3:
3 | (a) | T = 4g
λ (0.02)
= 4g
0.3
λ = 588(N) | B1
M1
A1
[3] | 1.1
3.3
1.1 | Resolve vertically (possibly implied by
subsequent working)
Use of Hooke’s law with their 4g
cao oe e.g. 60g
3 | (b) | e.g. spring stretched beyond its elastic limit
e.g. Hooke’s law no longer applies | B1
[1] | 2.2b | oe (any correct equivalent statement for
why the extension of the spring may not
be 0.1 m)
3 One end of a light elastic spring of natural length 0.3 m is attached to a fixed point. A mass of 4 kg is attached to the other end of the spring.

When the spring hangs vertically in equilibrium the extension of the spring is 0.02 m .
\begin{enumerate}[label=(\alph*)]
\item Determine the modulus of elasticity of the spring.

A student calculates that if the mass of 4 kg is removed and replaced with a mass of 20 kg the extension of the spring will be 0.1 m .
\item Suggest a reason why this extension may not be 0.1 m .
\end{enumerate}

\hfill \mbox{\textit{OCR MEI Further Mechanics Major 2021 Q3 [4]}}