CAIE FP1 2007 November — Question 2 5 marks

Exam BoardCAIE
ModuleFP1 (Further Pure Mathematics 1)
Year2007
SessionNovember
Marks5
PaperDownload PDF ↗
TopicPartial Fractions
TypeAdditional geometric or exponential factor
DifficultyStandard +0.8 This is a Further Maths question combining partial fractions with method of differences applied to a geometric series. While partial fractions is routine, recognizing how to telescope the series with the geometric factor (1/3)^(n+1) requires insight beyond standard techniques. The final limit evaluation adds another layer, making this moderately challenging but within reach for FP1 students.
Spec1.02y Partial fractions: decompose rational functions4.06b Method of differences: telescoping series

2 Express $$\frac { 2 n + 3 } { n ( n + 1 ) }$$ in partial fractions and hence use the method of differences to find $$\sum _ { n = 1 } ^ { N } \frac { 2 n + 3 } { n ( n + 1 ) } \left( \frac { 1 } { 3 } \right) ^ { n + 1 }$$ in terms of \(N\). Deduce the value of $$\sum _ { n = 1 } ^ { \infty } \frac { 2 n + 3 } { n ( n + 1 ) } \left( \frac { 1 } { 3 } \right) ^ { n + 1 }$$

2 Express

$$\frac { 2 n + 3 } { n ( n + 1 ) }$$

in partial fractions and hence use the method of differences to find

$$\sum _ { n = 1 } ^ { N } \frac { 2 n + 3 } { n ( n + 1 ) } \left( \frac { 1 } { 3 } \right) ^ { n + 1 }$$

in terms of $N$.

Deduce the value of

$$\sum _ { n = 1 } ^ { \infty } \frac { 2 n + 3 } { n ( n + 1 ) } \left( \frac { 1 } { 3 } \right) ^ { n + 1 }$$

\hfill \mbox{\textit{CAIE FP1 2007 Q2 [5]}}