CAIE FP1 2007 November — Question 3 6 marks

Exam BoardCAIE
ModuleFP1 (Further Pure Mathematics 1)
Year2007
SessionNovember
Marks6
PaperDownload PDF ↗
TopicProof by induction
TypeProve derivative formula
DifficultyChallenging +1.2 This is a structured induction proof requiring the product rule and chain rule to show the nth derivative has the stated form. While it involves higher derivatives and polynomial analysis, the induction framework is standard and the differentiation mechanics are routine for Further Maths students. The polynomial degree and leading coefficient verification adds mild complexity beyond basic induction proofs.
Spec1.07q Product and quotient rules: differentiation1.07r Chain rule: dy/dx = dy/du * du/dx and connected rates4.01a Mathematical induction: construct proofs

3 Prove by induction that, for all \(n \geqslant 1\), $$\frac { \mathrm { d } ^ { n } } { \mathrm {~d} x ^ { n } } \left( \mathrm { e } ^ { x ^ { 2 } } \right) = \mathrm { P } _ { n } ( x ) \mathrm { e } ^ { x ^ { 2 } } ,$$ where \(\mathrm { P } _ { n } ( x )\) is a polynomial in \(x\) of degree \(n\) with the coefficient of \(x ^ { n }\) equal to \(2 ^ { n }\).

3 Prove by induction that, for all $n \geqslant 1$,

$$\frac { \mathrm { d } ^ { n } } { \mathrm {~d} x ^ { n } } \left( \mathrm { e } ^ { x ^ { 2 } } \right) = \mathrm { P } _ { n } ( x ) \mathrm { e } ^ { x ^ { 2 } } ,$$

where $\mathrm { P } _ { n } ( x )$ is a polynomial in $x$ of degree $n$ with the coefficient of $x ^ { n }$ equal to $2 ^ { n }$.

\hfill \mbox{\textit{CAIE FP1 2007 Q3 [6]}}