CAIE FP1 2010 June — Question 6 8 marks

Exam BoardCAIE
ModuleFP1 (Further Pure Mathematics 1)
Year2010
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPolynomial Division & Manipulation
TypeStationary Points of Rational Functions
DifficultyStandard +0.8 This FP1 question requires multiple techniques: finding asymptotes (polynomial division for oblique asymptote), differentiation using quotient rule, proving an inequality involving the derivative for all points, and sketching. The proof that dy/dx > 1 everywhere requires completing the square or analyzing a quadratic expression, which demands insight beyond routine calculation. Multi-part with conceptual depth typical of Further Maths.
Spec1.02k Simplify rational expressions: factorising, cancelling, algebraic division1.02n Sketch curves: simple equations including polynomials1.07i Differentiate x^n: for rational n and sums1.07j Differentiate exponentials: e^(kx) and a^(kx)1.07m Tangents and normals: gradient and equations

6 The curve \(C\) has equation $$y = \frac { x ^ { 2 } - 3 x - 7 } { x + 1 }$$
  1. Obtain the equations of the asymptotes of \(C\).
  2. Show that \(\frac { \mathrm { d } y } { \mathrm {~d} x } > 1\) at all points of \(C\).
  3. Draw a sketch of \(C\).

AnswerMarks Guidance
(i) One asymptote is \(x = -1\)B1
\(y = x - 4 - \frac{3}{(x+1)}\)M1
Require \(y = x +\) non-zero constant. Other asymptote is \(y = x - 4\)A1 [3]
Alternatively for last two marks:
AnswerMarks Guidance
\(\mathbf{OR}\) \(x + k \approx (x^2 - 3x - 7)/(x+1)\) for large \(x \Rightarrow x^2 + (k+1)x + k \approx x^2 - 3x - 7\) for large \(x\) ⟹ \(k + 1 = -3 \Rightarrow k = -4\) ⟹ other asymptote is \(y = x - 4\)M1 A1
\(\mathbf{OR}\) \((x^2 - 3x - 7)/(x+1) = mx + c \Rightarrow (m-1)x^2 + (m + c + 3)x + c + 7 = 0\)M1
Put \(m - 1 = 0, m + c + 3 = 0\) to obtain other asymptote is \(y = x - 4\)A1
(ii) Obtains any correct result for \(\frac{dy}{dx}\)M1
\(\Rightarrow \ldots \Rightarrow \frac{dy}{dx} = [(x+1)^2 + 3]/[(x+1)^2] = 1 + \frac{3}{(x+1)^2}\)A1 [2]
No comment required.
AnswerMarks
(iii) Axes and asymptotes correctly placedB1
Right-hand branchB1
Left-hand branchB1
Deduct 1 overall for bad form(s) at infinity[3]
**(i)** One asymptote is $x = -1$ | B1 |

$y = x - 4 - \frac{3}{(x+1)}$ | M1 |

Require $y = x +$ non-zero constant. Other asymptote is $y = x - 4$ | A1 | [3]

**Alternatively for last two marks:**

$\mathbf{OR}$ $x + k \approx (x^2 - 3x - 7)/(x+1)$ for large $x \Rightarrow x^2 + (k+1)x + k \approx x^2 - 3x - 7$ for large $x$ ⟹ $k + 1 = -3 \Rightarrow k = -4$ ⟹ other asymptote is $y = x - 4$ | M1 A1 |

$\mathbf{OR}$ $(x^2 - 3x - 7)/(x+1) = mx + c \Rightarrow (m-1)x^2 + (m + c + 3)x + c + 7 = 0$ | M1 |

Put $m - 1 = 0, m + c + 3 = 0$ to obtain other asymptote is $y = x - 4$ | A1 |

**(ii)** Obtains any correct result for $\frac{dy}{dx}$ | M1 |

$\Rightarrow \ldots \Rightarrow \frac{dy}{dx} = [(x+1)^2 + 3]/[(x+1)^2] = 1 + \frac{3}{(x+1)^2}$ | A1 | [2]

No comment required.

**(iii)** Axes and asymptotes correctly placed | B1 |

Right-hand branch | B1 |

Left-hand branch | B1 |

Deduct 1 overall for bad form(s) at infinity | [3] |

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6 The curve $C$ has equation

$$y = \frac { x ^ { 2 } - 3 x - 7 } { x + 1 }$$

(i) Obtain the equations of the asymptotes of $C$.\\
(ii) Show that $\frac { \mathrm { d } y } { \mathrm {~d} x } > 1$ at all points of $C$.\\
(iii) Draw a sketch of $C$.

\hfill \mbox{\textit{CAIE FP1 2010 Q6 [8]}}