Edexcel C12 Specimen — Question 6 7 marks

Exam BoardEdexcel
ModuleC12 (Core Mathematics 1 & 2)
SessionSpecimen
Marks7
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Mark schemeDownload PDF ↗
TopicFactor & Remainder Theorem
TypeTwo unknowns with show-that step
DifficultyModerate -0.5 This is a straightforward application of the Remainder Theorem requiring students to substitute x=1 and x=-2, set up two simultaneous equations, and solve. The 'show that' in part (a) guides students through the process, making it easier than average for A-level but still requiring correct algebraic manipulation.
Spec1.02j Manipulate polynomials: expanding, factorising, division, factor theorem

6. $$\mathrm { f } ( x ) = x ^ { 4 } + x ^ { 3 } + 2 x ^ { 2 } + a x + b ,$$ where \(a\) and \(b\) are constants. When \(\mathrm { f } ( x )\) is divided by \(( x - 1 )\), the remainder is 7
  1. Show that \(a + b = 3\) When \(\mathrm { f } ( x )\) is divided by ( \(x + 2\) ), the remainder is - 8
  2. Find the value of \(a\) and the value of \(b\).

6.

$$\mathrm { f } ( x ) = x ^ { 4 } + x ^ { 3 } + 2 x ^ { 2 } + a x + b ,$$

where $a$ and $b$ are constants.

When $\mathrm { f } ( x )$ is divided by $( x - 1 )$, the remainder is 7
\begin{enumerate}[label=(\alph*)]
\item Show that $a + b = 3$

When $\mathrm { f } ( x )$ is divided by ( $x + 2$ ), the remainder is - 8
\item Find the value of $a$ and the value of $b$.
\end{enumerate}

\hfill \mbox{\textit{Edexcel C12  Q6 [7]}}