AQA Further AS Paper 1 2024 June — Question 11 3 marks

Exam BoardAQA
ModuleFurther AS Paper 1 (Further AS Paper 1)
Year2024
SessionJune
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMatrices
TypeMatrix multiplication
DifficultyModerate -0.8 This is a straightforward matrix multiplication with complex entries requiring careful arithmetic but no problem-solving or conceptual insight. The presence of complex numbers adds minor computational care, but the task is purely procedural—multiply rows by columns and simplify. Well below average difficulty for Further Maths.
Spec4.03b Matrix operations: addition, multiplication, scalar

11 The matrices \(\mathbf { A }\) and \(\mathbf { B }\) are given by $$\mathbf { A } = \left[ \begin{array} { c c } 3 \mathrm { i } & - 2 \\ a & - \mathrm { i } \end{array} \right] \quad \text { and } \quad \mathbf { B } = \left[ \begin{array} { c c } 4 & 5 \\ - 2 \mathrm { i } & - 1 \end{array} \right]$$ where \(a\) is a real number. Calculate the product \(\mathbf { A B }\) in terms of \(a\) Give your answer in its simplest form.
[0pt] [3 marks]

Question 11:
AnswerMarks Guidance
Correct method for at least two elements of AB: \(\mathbf{AB} = \begin{bmatrix} 3i & -2 \\ a & -i \end{bmatrix}\begin{bmatrix} 4 & 5 \\ -2i & -1 \end{bmatrix}\)M1 (1.1a)
Obtains \(4a-2\) in row 2 column 1: \(= \begin{bmatrix} 12i+4i & 15i+2 \\ 4a+2i^2 & 5a+i \end{bmatrix}\)B1 (1.1b)
Obtains \(\begin{bmatrix} 16i & 2+15i \\ 4a-2 & 5a+i \end{bmatrix}\)A1 (1.1b)
## Question 11:

Correct method for at least two elements of **AB**: $\mathbf{AB} = \begin{bmatrix} 3i & -2 \\ a & -i \end{bmatrix}\begin{bmatrix} 4 & 5 \\ -2i & -1 \end{bmatrix}$ | M1 (1.1a) | —

Obtains $4a-2$ in row 2 column 1: $= \begin{bmatrix} 12i+4i & 15i+2 \\ 4a+2i^2 & 5a+i \end{bmatrix}$ | B1 (1.1b) | —

Obtains $\begin{bmatrix} 16i & 2+15i \\ 4a-2 & 5a+i \end{bmatrix}$ | A1 (1.1b) | —

---
11 The matrices $\mathbf { A }$ and $\mathbf { B }$ are given by

$$\mathbf { A } = \left[ \begin{array} { c c } 
3 \mathrm { i } & - 2 \\
a & - \mathrm { i }
\end{array} \right] \quad \text { and } \quad \mathbf { B } = \left[ \begin{array} { c c } 
4 & 5 \\
- 2 \mathrm { i } & - 1
\end{array} \right]$$

where $a$ is a real number.

Calculate the product $\mathbf { A B }$ in terms of $a$\\
Give your answer in its simplest form.\\[0pt]
[3 marks]\\

\hfill \mbox{\textit{AQA Further AS Paper 1 2024 Q11 [3]}}