AQA Further AS Paper 1 2024 June — Question 10 6 marks

Exam BoardAQA
ModuleFurther AS Paper 1 (Further AS Paper 1)
Year2024
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCurve Sketching
TypeSolve f(x) > g(x) using sketch
DifficultyStandard +0.3 This is a straightforward Further Maths question involving sketching a rational function and solving an inequality graphically. Finding asymptotes of a simple rational function is routine, drawing a linear function is trivial, and reading off the solution from the sketch requires minimal problem-solving. While it's Further Maths content, the techniques are standard and mechanical, making it slightly easier than an average A-level question overall.
Spec1.02n Sketch curves: simple equations including polynomials1.02t Solve modulus equations: graphically with modulus function

10
  1. Write down the equations of the asymptotes of \(C\) 10
  2. The line \(L\) has equation $$y = - \frac { 2 } { 5 } x + 2$$ 10 (b) (i) Draw the line \(L\) on Figure 1 10 (b) (ii) Hence, or otherwise, solve the inequality $$\frac { 2 x - 10 } { 3 x - 5 } \leq - \frac { 2 } { 5 } x + 2$$

Question 10(a):
AnswerMarks Guidance
States \(x = \frac{5}{3}\) or \(y = \frac{2}{3}\)M1 (2.2a)
States \(x = \frac{5}{3}\) and \(y = \frac{2}{3}\) with no incorrect equations seenA1 (2.2a)
Question 10(b)(i):
AnswerMarks Guidance
Draws a straight line with negative gradient passing through \((0,2)\); accept freehand if intention is clearM1 (1.1a)
Draws a straight line passing through \((0,2)\) and \((5,0)\)A1 (1.1b)
Question 10(b)(ii):
AnswerMarks Guidance
Deduces one of the ranges \(x \leq 0\) or \(\frac{5}{3} < x \leq 5\); condone \(\frac{5}{3} \leq x \leq 5\) or \(\frac{5}{3} < x < 5\) for this mark only; ignore any incorrect rangesM1 (2.2a)
Deduces the solution \(x \leq 0\) , \(\frac{5}{3} < x \leq 5\)A1 (2.2a)
## Question 10(a):

States $x = \frac{5}{3}$ **or** $y = \frac{2}{3}$ | M1 (2.2a) | —

States $x = \frac{5}{3}$ **and** $y = \frac{2}{3}$ with no incorrect equations seen | A1 (2.2a) | —

---

## Question 10(b)(i):

Draws a straight line with negative gradient passing through $(0,2)$; accept freehand if intention is clear | M1 (1.1a) | —

Draws a straight line passing through $(0,2)$ and $(5,0)$ | A1 (1.1b) | —

---

## Question 10(b)(ii):

Deduces one of the ranges $x \leq 0$ **or** $\frac{5}{3} < x \leq 5$; condone $\frac{5}{3} \leq x \leq 5$ or $\frac{5}{3} < x < 5$ for this mark only; ignore any incorrect ranges | M1 (2.2a) | —

Deduces the solution $x \leq 0$ , $\frac{5}{3} < x \leq 5$ | A1 (2.2a) | —

---
10
\begin{enumerate}[label=(\alph*)]
\item Write down the equations of the asymptotes of $C$\\

10
\item The line $L$ has equation

$$y = - \frac { 2 } { 5 } x + 2$$

10 (b) (i) Draw the line $L$ on Figure 1

10 (b) (ii) Hence, or otherwise, solve the inequality

$$\frac { 2 x - 10 } { 3 x - 5 } \leq - \frac { 2 } { 5 } x + 2$$
\end{enumerate}

\hfill \mbox{\textit{AQA Further AS Paper 1 2024 Q10 [6]}}