AQA Further AS Paper 1 2024 June — Question 1 1 marks

Exam BoardAQA
ModuleFurther AS Paper 1 (Further AS Paper 1)
Year2024
SessionJune
Marks1
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicHyperbolic functions
TypeProve hyperbolic identity from exponentials
DifficultyEasy -1.8 This is a direct recall question of the fundamental hyperbolic identity cosh²x - sinh²x = 1, requiring only algebraic rearrangement to cosh²x = 1 + sinh²x. It's a multiple-choice question with no working required, testing basic knowledge rather than problem-solving or derivation skills.
Spec4.07c Hyperbolic identity: cosh^2(x) - sinh^2(x) = 1

1 Express \(\cosh ^ { 2 } x\) in terms of \(\sinh x\) Circle your answer. \(1 + \sinh ^ { 2 } x\) \(1 - \sinh ^ { 2 } x\) \(\sinh ^ { 2 } x - 1\) \(- 1 - \sinh ^ { 2 } x\)

Question 1:
AnswerMarks Guidance
AnswerMarks Guidance
\(1 + \sinh^2 x\)B1 (AO1.1b) Circles the 1st answer
Total1
## Question 1:
| Answer | Marks | Guidance |
|--------|-------|----------|
| $1 + \sinh^2 x$ | B1 (AO1.1b) | Circles the 1st answer |
| **Total** | **1** | |

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1 Express $\cosh ^ { 2 } x$ in terms of $\sinh x$\\
Circle your answer.\\
$1 + \sinh ^ { 2 } x$\\
$1 - \sinh ^ { 2 } x$\\
$\sinh ^ { 2 } x - 1$\\
$- 1 - \sinh ^ { 2 } x$

\hfill \mbox{\textit{AQA Further AS Paper 1 2024 Q1 [1]}}