4 The line \(L\) has vector equation $$\mathbf { r } = \left[ \begin{array} { c } 4
- 7
0 \end{array} \right] + \lambda \left[ \begin{array} { c } - 9
1
3 \end{array} \right]$$ Give the equation of \(L\) in Cartesian form.
Tick ( ✓ ) one box.
\(\frac { x + 4 } { - 9 } = \frac { y - 7 } { 1 } = \frac { z } { 3 }\)
\includegraphics[max width=\textwidth, alt={}, center]{47b12ae4-ca3f-472c-9d15-2ef17a2a4d87-03_108_109_1398_993}
\(\frac { x - 4 } { - 9 } = \frac { y + 7 } { 1 } = \frac { z } { 3 }\)
\includegraphics[max width=\textwidth, alt={}, center]{47b12ae4-ca3f-472c-9d15-2ef17a2a4d87-03_108_111_1567_991}
\(\frac { x + 9 } { 4 } = \frac { y - 1 } { - 7 } , z = 3\) □
\(\frac { x - 9 } { 4 } = \frac { y + 1 } { - 7 } , z = 3\) □