Prove hyperbolic identity from exponentials

A question is this type if and only if it asks to prove a hyperbolic identity (e.g., cosh²x - sinh²x = 1, sinh 2x = 2sinh x cosh x, or double angle formulas) starting from the exponential definitions of sinh and cosh.

16 questions · Standard +0.2

4.07a Hyperbolic definitions: sinh, cosh, tanh as exponentials
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CAIE Further Paper 2 2022 June Q2
8 marks Standard +0.3
2
  1. Starting from the definitions of cosh and sinh in terms of exponentials, prove that $$\cosh 2 x = 2 \sinh ^ { 2 } x + 1$$
  2. Find the set of values of \(k\) for which \(\cosh 2 \mathrm { x } = \mathrm { ksinh } \mathrm { x }\) has two distinct real roots.
CAIE Further Paper 2 2023 June Q8
14 marks Standard +0.8
8
  1. Starting from the definitions of sech and tanh in terms of exponentials, prove that $$1 - \operatorname { sech } ^ { 2 } t = \tanh ^ { 2 } t$$ \includegraphics[max width=\textwidth, alt={}]{d3ddf5ce-4399-4438-ab67-7bdb2e1bea6e-14_77_1547_360_347} ......................................................................................................................................... ......................................................................................................................................... . ........................................................................................................................................ ........................................................................................................................................ ....................................................................................................................................... \includegraphics[max width=\textwidth, alt={}, center]{d3ddf5ce-4399-4438-ab67-7bdb2e1bea6e-14_72_1573_911_324} \includegraphics[max width=\textwidth, alt={}, center]{d3ddf5ce-4399-4438-ab67-7bdb2e1bea6e-14_67_1570_1005_324} The curve \(C\) has parametric equations $$\mathrm { x } = \frac { 1 } { 2 } \tanh ^ { 2 } \mathrm { t } + \text { Insecht } , \quad \mathrm { y } = 1 + \tanh ^ { 4 } \mathrm { t } , \quad \text { for } t > 0$$
  2. Show that \(\frac { d y } { d x } = - 4 \operatorname { sech } ^ { 2 } t\).
  3. Find the coordinates of the point on \(C\) with \(\frac { d ^ { 2 } y } { d x ^ { 2 } } = - \frac { 9 } { 2 }\), giving your answer in the form \(( a + \ln b , c )\) where \(a , b\) and \(c\) are rational numbers.
    If you use the following page to complete the answer to any question, the question number must be clearly shown.
CAIE Further Paper 2 2023 June Q8
14 marks Standard +0.8
8
  1. Starting from the definitions of sech and tanh in terms of exponentials, prove that $$1 - \operatorname { sech } ^ { 2 } t = \tanh ^ { 2 } t$$ \includegraphics[max width=\textwidth, alt={}]{482b2236-1f1b-4c53-a1bc-0277cf63dc62-14_77_1547_360_347} ......................................................................................................................................... ......................................................................................................................................... . ........................................................................................................................................ ........................................................................................................................................ ....................................................................................................................................... \includegraphics[max width=\textwidth, alt={}, center]{482b2236-1f1b-4c53-a1bc-0277cf63dc62-14_72_1573_911_324} \includegraphics[max width=\textwidth, alt={}, center]{482b2236-1f1b-4c53-a1bc-0277cf63dc62-14_67_1573_1005_324} The curve \(C\) has parametric equations $$\mathrm { x } = \frac { 1 } { 2 } \tanh ^ { 2 } \mathrm { t } + \text { Insecht } , \quad \mathrm { y } = 1 + \tanh ^ { 4 } \mathrm { t } , \quad \text { for } t > 0$$
  2. Show that \(\frac { d y } { d x } = - 4 \operatorname { sech } ^ { 2 } t\).
  3. Find the coordinates of the point on \(C\) with \(\frac { d ^ { 2 } y } { d x ^ { 2 } } = - \frac { 9 } { 2 }\), giving your answer in the form \(( a + \ln b , c )\) where \(a , b\) and \(c\) are rational numbers.
    If you use the following page to complete the answer to any question, the question number must be clearly shown.
CAIE Further Paper 2 2023 November Q6
14 marks Standard +0.3
6
  1. Starting from the definitions of cosh and sinh in terms of exponentials, prove that $$\sinh 2 x = 2 \sinh x \cosh x$$ \includegraphics[max width=\textwidth, alt={}, center]{dffdf588-eb26-4d08-b1a3-a0226f5e7763-10_67_1550_374_347} \includegraphics[max width=\textwidth, alt={}, center]{dffdf588-eb26-4d08-b1a3-a0226f5e7763-10_58_1569_475_328} \includegraphics[max width=\textwidth, alt={}, center]{dffdf588-eb26-4d08-b1a3-a0226f5e7763-10_58_1569_566_328} \includegraphics[max width=\textwidth, alt={}]{dffdf588-eb26-4d08-b1a3-a0226f5e7763-10_54_1566_657_328} ....................................................................................................................................................... . \includegraphics[max width=\textwidth, alt={}, center]{dffdf588-eb26-4d08-b1a3-a0226f5e7763-10_54_1570_840_324} \includegraphics[max width=\textwidth, alt={}, center]{dffdf588-eb26-4d08-b1a3-a0226f5e7763-10_53_1570_932_324} \includegraphics[max width=\textwidth, alt={}, center]{dffdf588-eb26-4d08-b1a3-a0226f5e7763-10_53_1570_1023_324}
  2. Using the substitution \(\mathrm { u } = \sinh \mathrm { x }\), find \(\int \sinh ^ { 2 } 2 x \cosh x \mathrm { dx }\).
  3. Find the particular solution of the differential equation $$\frac { d y } { d x } + y \tanh x = \sinh ^ { 2 } 2 x$$ given that \(y = 4\) when \(x = 0\). Give your answer in the form \(y = f ( x )\).
OCR FP2 Specimen Q1
6 marks Standard +0.3
1
  1. Starting from the definition of \(\cosh x\) in terms of \(\mathrm { e } ^ { x }\), show that \(\cosh 2 x = 2 \cosh ^ { 2 } x - 1\).
  2. Given that \(\cosh 2 x = k\), where \(k > 1\), express each of \(\cosh x\) and \(\sinh x\) in terms of \(k\).
Edexcel CP2 2024 June Q1
7 marks Standard +0.3
  1. (a) Using the definition of \(\sinh x\) in terms of exponentials, prove that
$$4 \sinh ^ { 3 } x + 3 \sinh x \equiv \sinh 3 x$$ (b) Hence solve the equation $$\sinh 3 x = 19 \sinh x$$ giving your answers as simplified natural logarithms where appropriate.
AQA Further AS Paper 1 2021 June Q6
2 marks Easy -1.2
6 Prove the identity $$\cosh ^ { 2 } x - \sinh ^ { 2 } x = 1$$
AQA Further AS Paper 1 2024 June Q1
1 marks Easy -1.8
1 Express \(\cosh ^ { 2 } x\) in terms of \(\sinh x\) Circle your answer. \(1 + \sinh ^ { 2 } x\) \(1 - \sinh ^ { 2 } x\) \(\sinh ^ { 2 } x - 1\) \(- 1 - \sinh ^ { 2 } x\)
AQA Further Paper 1 2020 June Q14
6 marks Challenging +1.2
14
  1. Given that $$\sinh ( A + B ) = \sinh A \cosh B + \cosh A \sinh B$$ express \(\sinh ( m + 1 ) x\) and \(\sinh ( m - 1 ) x\) in terms of \(\sinh m x , \cosh m x , \sinh x\) and \(\cosh x\) 14
  2. Hence find the sum of the series $$C _ { n } = \cosh x + \cosh 2 x + \cdots + \cosh n x$$ in terms of \(\sinh x , \sinh n x\) and \(\sinh ( n + 1 ) x\) Do not write \includegraphics[max width=\textwidth, alt={}, center]{44e22a98-6424-4fb1-8a37-c965773cb7b6-30_2491_1736_219_139}
Edexcel S2 2024 October Q7
Standard +0.3
  1. The continuous random variable \(X\) has probability density function given by
$$f ( x ) = \begin{cases} a x & 0 \leqslant x \leqslant 4 \\ b x + c & 4 < x \leqslant 8 \\ 0 & \text { otherwise } \end{cases}$$ where \(a\), \(b\) and \(c\) are constants. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{6e6f7a1a-b577-4f28-a7a9-557b9d325851-24_389_1013_630_529} \captionsetup{labelformat=empty} \caption{Figure 1}
\end{figure} Figure 1 shows the graph of the probability density function \(\mathrm { f } ( x )\) The graph consists of two straight line segments of equal length joined at the point where \(x = 4\)
  1. Show that \(a = \frac { 1 } { 16 }\)
  2. Hence find
    1. the value of \(b\)
    2. the value of \(c\)
  3. Using algebraic integration, show that \(\operatorname { Var } ( X ) = \frac { 8 } { 3 }\)
  4. Find, to 2 decimal places, the lower quartile and the upper quartile of \(X\) A statistician claims that $$\mathrm { P } ( - \sigma < X - \mu < \sigma ) > 0.5$$ where \(\mu\) and \(\sigma\) are the mean and standard deviation of \(X\)
  5. Show that the statistician's claim is correct.
CAIE Further Paper 2 2023 November Q6
14 marks Standard +0.8
  1. Starting from the definitions of cosh and sinh in terms of exponentials, prove that $$\sinh 2x = 2\sinh x\cosh x.$$ [3]
  2. Using the substitution \(u = \sinh x\), find \(\int \sinh^2 2x\cosh x\,dx\). [4]
  3. Find the particular solution of the differential equation $$\frac{dy}{dx} + y\tanh x = \sinh^2 2x,$$ given that \(y = 4\) when \(x = 0\). Give your answer in the form \(y = f(x)\). [7]
Edexcel FP3 Q7
4 marks Challenging +1.2
Prove that \(\sinh(i\pi - \theta) = \sinh \theta\). [4]
Edexcel FP3 Q21
7 marks Standard +0.3
Using the definitions of \(\cosh x\) and \(\sinh x\) in terms of exponentials,
  1. prove that \(\cosh^2 x - \sinh^2 x = 1\), [3]
  2. solve \(\operatorname{cosech} x - 2 \coth x = 2\), giving your answer in the form \(k \ln a\), where \(k\) and \(a\) are integers. [4]
AQA FP2 2011 June Q2
10 marks Standard +0.3
  1. Use the definitions of \(\cosh \theta\) and \(\sinh \theta\) in terms of \(e^\theta\) to show that $$\cosh x \cosh y - \sinh x \sinh y = \cosh(x - y)$$ [4 marks]
  2. It is given that \(x\) satisfies the equation $$\cosh(x - \ln 2) = \sinh x$$
    1. Show that \(\tanh x = \frac{5}{4}\). [4 marks]
    2. Express \(x\) in the form \(\frac{1}{2} \ln a\). [2 marks]
AQA Further Paper 1 2023 June Q12
6 marks Standard +0.3
  1. Starting from the identities for \(\sinh 2x\) and \(\cosh 2x\), prove the identity $$\tanh 2x = \frac{2 \tanh x}{1 + \tanh^2 x}$$ [2 marks]
    1. The function f is defined by $$f(x) = \tanh x \quad (x > 0)$$ State the range of f [1 mark]
    2. Use part (a) and part (b)(i) to prove that \(\tanh 2x > \tanh x\) if \(x > 0\) [3 marks]
AQA Further Paper 1 Specimen Q2
2 marks Moderate -0.8
Use the definitions of \(\cosh x\) and \(\sinh x\) in terms of \(e^x\) and \(e^{-x}\) to show that \(\cosh^2 x - \sinh^2 x = 1\) [2 marks]