AQA D2 2012 June — Question 2 10 marks

Exam BoardAQA
ModuleD2 (Decision Mathematics 2)
Year2012
SessionJune
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMatchings and Allocation
TypeHungarian algorithm with restrictions
DifficultyStandard +0.3 This is a standard Hungarian algorithm application with a minor complication (two forbidden assignments). The algorithm itself is mechanical and well-practiced in D2, and handling restrictions by using large dummy values is a routine technique explicitly taught for this scenario.
Spec7.04a Shortest path: Dijkstra's algorithm7.04b Minimum spanning tree: Prim's and Kruskal's algorithms

2 The times taken in minutes for five people, Ann, Baz, Cal, Di and Ez, to complete each of five different tasks are recorded in the table below. Neither Ann nor Di can do task 2, as indicated by the asterisks in the table.

Question 2:
Part (a)
AnswerMarks Guidance
AnswerMarks Guidance
Row reduction (subtract row minima): rows mins are 13, 18, 15, 16, 20M1 Correct row reduction
Reduced matrix shown correctlyA1
Cover zeros with 4 linesA1 Correct covering shown
Total:3
Part (b)
AnswerMarks Guidance
AnswerMarks Guidance
Column reduction applied to uncovered elementsM1 Correct adjustment value identified
Adjustment made to produce table requiring 5 linesA1 A1
Total:3
Part (c)
AnswerMarks Guidance
AnswerMarks Guidance
Optimal allocations identified from zero positionsM1
e.g. Ann–Task1, Baz–Task4, Cal–Task2, Di–Task3, Ez–Task5A1 A1 Award marks for valid complete allocations
Total:3
Part (d)
AnswerMarks Guidance
AnswerMarks Guidance
Minimum total time = \(\mathbf{84}\) minutesB1
Total:1
# Question 2:

## Part (a)

| Answer | Marks | Guidance |
|--------|-------|----------|
| Row reduction (subtract row minima): rows mins are 13, 18, 15, 16, 20 | M1 | Correct row reduction |
| Reduced matrix shown correctly | A1 | |
| Cover zeros with 4 lines | A1 | Correct covering shown |
| Total: | **3** | |

## Part (b)

| Answer | Marks | Guidance |
|--------|-------|----------|
| Column reduction applied to uncovered elements | M1 | Correct adjustment value identified |
| Adjustment made to produce table requiring 5 lines | A1 A1 | |
| Total: | **3** | |

## Part (c)

| Answer | Marks | Guidance |
|--------|-------|----------|
| Optimal allocations identified from zero positions | M1 | |
| e.g. Ann–Task1, Baz–Task4, Cal–Task2, Di–Task3, Ez–Task5 | A1 A1 | Award marks for valid complete allocations |
| Total: | **3** | |

## Part (d)

| Answer | Marks | Guidance |
|--------|-------|----------|
| Minimum total time = $\mathbf{84}$ minutes | B1 | |
| Total: | **1** | |

---
2 The times taken in minutes for five people, Ann, Baz, Cal, Di and Ez, to complete each of five different tasks are recorded in the table below. Neither Ann nor Di can do task 2, as indicated by the asterisks in the table.

\hfill \mbox{\textit{AQA D2 2012 Q2 [10]}}