AQA FP2 2009 June — Question 3 8 marks

Exam BoardAQA
ModuleFP2 (Further Pure Mathematics 2)
Year2009
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicRoots of polynomials
TypeComplex roots with real coefficients
DifficultyStandard +0.3 This is a standard Further Maths question on complex roots with real coefficients. It requires knowing that complex roots come in conjugate pairs, then applying Vieta's formulas systematically. The calculations are straightforward (finding |α|², sum of roots, product of roots) with no conceptual surprises—slightly above average only because it's Further Maths content.
Spec4.02g Conjugate pairs: real coefficient polynomials4.05a Roots and coefficients: symmetric functions

3 The cubic equation $$z ^ { 3 } + p z ^ { 2 } + 25 z + q = 0$$ where \(p\) and \(q\) are real, has a root \(\alpha = 2 - 3 \mathrm { i }\).
  1. Write down another non-real root, \(\beta\), of this equation.
  2. Find:
    1. the value of \(\alpha \beta\);
    2. the third root, \(\gamma\), of the equation;
    3. the values of \(p\) and \(q\).

AnswerMarks Guidance
(a) \(2 + 3i\)B1 1 mark
(b)(i) \(\alpha\beta = 13\)B1 1 mark
(ii) \(\alpha\beta + \beta\gamma + \gamma\alpha = 25\)M1 M1A0 for -25 (no ft)
\(\gamma(\alpha + \beta) = 12\)A1F
\(\gamma = 3\)A1F 3 marks
(iii) \(p = -\sum\alpha = -7\)M1 M1 for a correct method for either \(p\) or \(q\)
\(q = -\alpha\beta\gamma = -39\)A1F A1F
Alternative for (b)(ii) and (iii):
AnswerMarks Guidance
(ii) Attempt at \((\overline{z} - 2 + 3i)(\overline{z} - 2 - 3i)\)(M1)
\(z^2 - 4z + 13\)(A1)
cubic is \((z^2 - 4z + 13)(\overline{z} - 3) \cdots \gamma = 3\)(A1) (3)
(iii) Multiply out or pick out coefficients(M1)
\(p = -7, q = -39\)(A1, A1) (3)
Total: 8 marks
**(a)** $2 + 3i$ | B1 | 1 mark

**(b)(i)** $\alpha\beta = 13$ | B1 | 1 mark

**(ii)** $\alpha\beta + \beta\gamma + \gamma\alpha = 25$ | M1 | M1A0 for -25 (no ft)

$\gamma(\alpha + \beta) = 12$ | A1F |

$\gamma = 3$ | A1F | 3 marks | ft error in $\alpha\beta$

**(iii)** $p = -\sum\alpha = -7$ | M1 | M1 for a correct method for either $p$ or $q$

$q = -\alpha\beta\gamma = -39$ | A1F | A1F | 3 marks | ft from previous errors; $p$ and $q$ must be real. For sign errors in $p$ and $q$ allow M1 but A0

**Alternative for (b)(ii) and (iii):**

**(ii)** Attempt at $(\overline{z} - 2 + 3i)(\overline{z} - 2 - 3i)$ | (M1) |

$z^2 - 4z + 13$ | (A1) |

cubic is $(z^2 - 4z + 13)(\overline{z} - 3) \cdots \gamma = 3$ | (A1) | (3)

**(iii)** Multiply out or pick out coefficients | (M1) |

$p = -7, q = -39$ | (A1, A1) | (3)

**Total: 8 marks**
3 The cubic equation

$$z ^ { 3 } + p z ^ { 2 } + 25 z + q = 0$$

where $p$ and $q$ are real, has a root $\alpha = 2 - 3 \mathrm { i }$.
\begin{enumerate}[label=(\alph*)]
\item Write down another non-real root, $\beta$, of this equation.
\item Find:
\begin{enumerate}[label=(\roman*)]
\item the value of $\alpha \beta$;
\item the third root, $\gamma$, of the equation;
\item the values of $p$ and $q$.
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{AQA FP2 2009 Q3 [8]}}