OCR MEI Further Pure Core AS 2020 November — Question 1 3 marks

Exam BoardOCR MEI
ModuleFurther Pure Core AS (Further Pure Core AS)
Year2020
SessionNovember
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSequences and series, recurrence and convergence
TypeMethod of differences with given identity
DifficultyModerate -0.3 This is a straightforward telescoping series question where the identity is already given in the required form. Students simply need to write out the first few and last few terms to see the cancellation pattern, then evaluate what remains: 1 + 1/2 - 1/50 - 1/51. While it requires careful bookkeeping and fraction arithmetic, it's a standard textbook exercise with no conceptual difficulty or novel insight required, making it slightly easier than average.
Spec1.04g Sigma notation: for sums of series4.06b Method of differences: telescoping series

1 In this question you must show detailed reasoning. Find \(\sum _ { r = 2 } ^ { 50 } \left( \frac { 1 } { r - 1 } - \frac { 1 } { r + 1 } \right)\), expressing the answer as an exact fraction.

Question 1:
AnswerMarks
1DR
50  1 1 
∑ −
 
r−1 r+1
r=2
 1 1 1 1 1 1 1 1 1 1 
= 1− + − + −...+ − + − + −
 3 2 4 3 47 49 48 50 49 51
 1 1 1 
= 1+ − −
 2 50 51
1862
=
AnswerMarks
1275M1
A1*
A1cao
AnswerMarks
[3]2.4
2.2a
AnswerMarks
1.1enough terms to show
cancellation clearly
1 1
or...+ −
n−1 n+1
AnswerMarks
dep A1*1 1
condone ...+ −
r−1 r+1
Question 1:
1 | DR
50  1 1 
∑ −
 
r−1 r+1
r=2
 1 1 1 1 1 1 1 1 1 1 
= 1− + − + −...+ − + − + −

 3 2 4 3 47 49 48 50 49 51
 1 1 1 
= 1+ − −

 2 50 51
1862
=
1275 | M1
A1*
A1cao
[3] | 2.4
2.2a
1.1 | enough terms to show
cancellation clearly
1 1
or...+ −
n−1 n+1
dep A1* | 1 1
condone ...+ −
r−1 r+1
1 In this question you must show detailed reasoning.
Find $\sum _ { r = 2 } ^ { 50 } \left( \frac { 1 } { r - 1 } - \frac { 1 } { r + 1 } \right)$, expressing the answer as an exact fraction.

\hfill \mbox{\textit{OCR MEI Further Pure Core AS 2020 Q1 [3]}}