AQA FP1 2009 January — Question 6 10 marks

Exam BoardAQA
ModuleFP1 (Further Pure Mathematics 1)
Year2009
SessionJanuary
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPartial Fractions
TypeRational curve sketching with asymptotes and inequalities
DifficultyModerate -0.3 This is a routine Further Maths curve sketching question requiring identification of vertical asymptotes (from denominator zeros), horizontal asymptote (from degree comparison), x-intercepts (from numerator zeros), and sign analysis. While it involves multiple steps, each is standard technique with no novel insight required. The 'no stationary points' hint simplifies the sketch, and part (b) follows directly from the sketch.
Spec1.02g Inequalities: linear and quadratic in single variable1.02k Simplify rational expressions: factorising, cancelling, algebraic division1.02n Sketch curves: simple equations including polynomials

6 A curve has equation $$y = \frac { ( x - 1 ) ( x - 3 ) } { x ( x - 2 ) }$$
    1. Write down the equations of the three asymptotes of this curve.
    2. State the coordinates of the points at which the curve intersects the \(x\)-axis.
    3. Sketch the curve.
      (You are given that the curve has no stationary points.)
  1. Hence, or otherwise, solve the inequality $$\frac { ( x - 1 ) ( x - 3 ) } { x ( x - 2 ) } < 0$$

Question 6(a)(i):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
Asymptotes \(x=0\), \(x=2\), \(y=1\)\(\text{B1}\times3\)
Total3
Question 6(a)(ii):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
Intersections at \((1,0)\) and \((3,0)\)B1
Total1
Question 6(a)(iii):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
At least one branch approaching asymptotesB1
Each branch\(\text{B1}\times3\)
Total4
Question 6(b):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(0 < x < 1,\ 2 < x < 3\)B1, B1 Allow B1 if one repeated error occurs, eg \(\leq\) for \(<\)
Alternative: Complete correct algebraic methodM1A1 (2)
Total10
## Question 6(a)(i):

| Answer/Working | Marks | Guidance |
|---|---|---|
| Asymptotes $x=0$, $x=2$, $y=1$ | $\text{B1}\times3$ | |
| **Total** | **3** | |

## Question 6(a)(ii):

| Answer/Working | Marks | Guidance |
|---|---|---|
| Intersections at $(1,0)$ and $(3,0)$ | B1 | |
| **Total** | **1** | |

## Question 6(a)(iii):

| Answer/Working | Marks | Guidance |
|---|---|---|
| At least one branch approaching asymptotes | B1 | |
| Each branch | $\text{B1}\times3$ | |
| **Total** | **4** | |

## Question 6(b):

| Answer/Working | Marks | Guidance |
|---|---|---|
| $0 < x < 1,\ 2 < x < 3$ | B1, B1 | Allow B1 if one repeated error occurs, eg $\leq$ for $<$ |
| **Alternative:** Complete correct algebraic method | M1A1 | (2) |
| **Total** | **10** | |

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6 A curve has equation

$$y = \frac { ( x - 1 ) ( x - 3 ) } { x ( x - 2 ) }$$
\begin{enumerate}[label=(\alph*)]
\item \begin{enumerate}[label=(\roman*)]
\item Write down the equations of the three asymptotes of this curve.
\item State the coordinates of the points at which the curve intersects the $x$-axis.
\item Sketch the curve.\\
(You are given that the curve has no stationary points.)
\end{enumerate}\item Hence, or otherwise, solve the inequality

$$\frac { ( x - 1 ) ( x - 3 ) } { x ( x - 2 ) } < 0$$
\end{enumerate}

\hfill \mbox{\textit{AQA FP1 2009 Q6 [10]}}