AQA C3 2011 January — Question 5 6 marks

Exam BoardAQA
ModuleC3 (Core Mathematics 3)
Year2011
SessionJanuary
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIntegration by Parts
TypeIndependent multi-part (different techniques)
DifficultyModerate -0.3 Part (a) is a straightforward logarithmic integration requiring simple substitution or recognition. Part (b) is a standard textbook application of integration by parts with no complications. Both are routine C3-level exercises requiring direct application of learned techniques with no problem-solving insight needed, making this slightly easier than average.
Spec1.08c Integrate e^(kx), 1/x, sin(kx), cos(kx)1.08i Integration by parts

5
  1. Find \(\int \frac { 1 } { 3 + 2 x } \mathrm {~d} x\).
  2. By using integration by parts, find \(\int x \sin \frac { x } { 2 } \mathrm {~d} x\).

Question 5:
Part (a)
AnswerMarks Guidance
AnswerMark Guidance
\(\frac{1}{2}\ln(3+2x) + c\)M1 A1 M1 for \(k\ln(3+2x)\); A1 for correct coefficient \(\frac{1}{2}\)
Part (b)
AnswerMarks Guidance
AnswerMark Guidance
\(u = x\), \(\frac{dv}{dx} = \sin\frac{x}{2}\); \(\frac{du}{dx} = 1\), \(v = -2\cos\frac{x}{2}\)M1 Correct parts assignment and differentiation/integration
\(= -2x\cos\frac{x}{2} + \int 2\cos\frac{x}{2}\,dx\)A1 Correct expression after applying parts
\(= -2x\cos\frac{x}{2} + 4\sin\frac{x}{2} + c\)A1 A1 A1 for each term correct
# Question 5:

## Part (a)
| Answer | Mark | Guidance |
|--------|------|----------|
| $\frac{1}{2}\ln(3+2x) + c$ | M1 A1 | M1 for $k\ln(3+2x)$; A1 for correct coefficient $\frac{1}{2}$ |

## Part (b)
| Answer | Mark | Guidance |
|--------|------|----------|
| $u = x$, $\frac{dv}{dx} = \sin\frac{x}{2}$; $\frac{du}{dx} = 1$, $v = -2\cos\frac{x}{2}$ | M1 | Correct parts assignment and differentiation/integration |
| $= -2x\cos\frac{x}{2} + \int 2\cos\frac{x}{2}\,dx$ | A1 | Correct expression after applying parts |
| $= -2x\cos\frac{x}{2} + 4\sin\frac{x}{2} + c$ | A1 A1 | A1 for each term correct |
5
\begin{enumerate}[label=(\alph*)]
\item Find $\int \frac { 1 } { 3 + 2 x } \mathrm {~d} x$.
\item By using integration by parts, find $\int x \sin \frac { x } { 2 } \mathrm {~d} x$.
\end{enumerate}

\hfill \mbox{\textit{AQA C3 2011 Q5 [6]}}