OCR PURE — Question 1 2 marks

Exam BoardOCR
ModulePURE
Marks2
PaperDownload PDF ↗
TopicFactor & Remainder Theorem
TypeSingle unknown constant
DifficultyModerate -0.8 This is a straightforward application of the factor theorem requiring substitution of x=2 into the polynomial and solving a simple linear equation for k. It's a single-step problem testing basic recall of the factor theorem with minimal algebraic manipulation, making it easier than the average A-level question.
Spec1.02j Manipulate polynomials: expanding, factorising, division, factor theorem
1 Given that \(( x - 2 )\) is a factor of \(2 x ^ { 3 } + k x - 4\), find the value of the constant \(k\).
Question 1:
AnswerMarks Guidance
\(2(2)^3 + 2k - 4 = 0\)M1 (AO 1.1) Sets \(f(2)\) equal to 0; or any other complete method
\(k = -6\)A1 (AO 1.1)
Total: [2]
## Question 1:

$2(2)^3 + 2k - 4 = 0$ | M1 (AO 1.1) | Sets $f(2)$ equal to 0; or any other complete method

$k = -6$ | A1 (AO 1.1) |

**Total: [2]**

---
1 Given that $( x - 2 )$ is a factor of $2 x ^ { 3 } + k x - 4$, find the value of the constant $k$.

\hfill \mbox{\textit{OCR PURE  Q1 [2]}}
This paper (12 questions)
View full paper
Q1 2 Q2 3 Q3 5 Q4 5 Q5 9 Q6 6 Q7 9 Q8 11 Q9 3 Q10 8 Q11 7 Q12 7