OCR PURE — Question 3 5 marks

Exam BoardOCR
ModulePURE
Marks5
PaperDownload PDF ↗
TopicArithmetic Sequences and Series
TypeReal-world AP: find term or total
DifficultyModerate -0.8 This is a straightforward application of linear modeling requiring finding gradient from two points and checking consistency with a third point. The arithmetic is simple (gradient = 450/6 = 75), and part (b) only requires substituting t=0 to verify the model gives £1900. No complex problem-solving or conceptual depth required—below average difficulty for A-level.
Spec1.03a Straight lines: equation forms y=mx+c, ax+by+c=0

3 Sam invested in a shares scheme. The value, \(\pounds V\), of Sam's shares was reported \(t\) months after investment.
  • Exactly 6 months after investment, the value of Sam's shares was \(\pounds 2375\).
  • Exactly 1 year after investment, the value of Sam's shares was \(\pounds 2825\).
    1. Using a straight-line model, determine an equation for \(V\) in terms of \(t\).
Sam's original investment in the scheme was \(\pounds 1900\).
  • Explain whether or not this fact supports the use of the straight-line model in part (a).

  • Question 3(a):
    AnswerMarks Guidance
    \(V = at + b\); \(2375 = 6a + b\), \(2825 = 12a + b\)M1* (AO 3.3) Using a linear model to set up two equations with the values given; or correct attempt to find gradient
    Solving their two equations to find a linear model, possibly BCM1dep* (AO 3.1a) Using *their* gradient to find a linear model
    \(V = 75t + 1925\)A1 (AO 1.1) cao
    Total: [3]
    Question 3(b):
    AnswerMarks Guidance
    When \(t = 0\), \(V = 1925\)B1ft (AO 3.4) Uses model and states initial investment is their '\(b\)'; only ft a linear model from part (a)
    Compare *their* "1925" with 1900 and make a sensible comment about whether the straight-line model in part (a) is supported or notB1ft (AO 3.5a)
    Total: [2]
    ## Question 3(a):
    
    $V = at + b$; $2375 = 6a + b$, $2825 = 12a + b$ | M1* (AO 3.3) | Using a linear model to set up two equations with the values given; or correct attempt to find gradient
    
    Solving their two equations to find a linear model, possibly BC | M1dep* (AO 3.1a) | Using *their* gradient to find a linear model
    
    $V = 75t + 1925$ | A1 (AO 1.1) | cao
    
    **Total: [3]**
    
    ## Question 3(b):
    
    When $t = 0$, $V = 1925$ | B1ft (AO 3.4) | Uses model and states initial investment is their '$b$'; only ft a linear model from part (a)
    
    Compare *their* "1925" with 1900 and make a sensible comment about whether the straight-line model in part (a) is supported or not | B1ft (AO 3.5a) |
    
    **Total: [2]**
    
    ---
    3 Sam invested in a shares scheme. The value, $\pounds V$, of Sam's shares was reported $t$ months after investment.
    
    \begin{itemize}
      \item Exactly 6 months after investment, the value of Sam's shares was $\pounds 2375$.
      \item Exactly 1 year after investment, the value of Sam's shares was $\pounds 2825$.
    \begin{enumerate}[label=(\alph*)]
    \item Using a straight-line model, determine an equation for $V$ in terms of $t$.
    \end{itemize}
    
    Sam's original investment in the scheme was $\pounds 1900$.
    \item Explain whether or not this fact supports the use of the straight-line model in part (a).
    \end{enumerate}
    
    \hfill \mbox{\textit{OCR PURE  Q3 [5]}}