CAIE FP2 2013 November — Question 7 7 marks

Exam BoardCAIE
ModuleFP2 (Further Pure Mathematics 2)
Year2013
SessionNovember
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicT-tests (unknown variance)
TypeSingle sample t-test
DifficultyStandard +0.3 This is a straightforward one-sample t-test with all necessary summary statistics provided. Students need to calculate the sample mean and standard deviation, then apply the standard t-test procedure with given hypotheses. While it requires knowledge of hypothesis testing mechanics, it's a direct application of a standard technique with no conceptual complications or multi-step reasoning beyond the standard algorithm.
Spec5.05c Hypothesis test: normal distribution for population mean

7 A random sample of 10 observations of a normally distributed random variable \(X\) gave the following summarised data, where \(\bar { x }\) denotes the sample mean. $$\Sigma x = 70.4 \quad \Sigma ( x - \bar { x } ) ^ { 2 } = 8.48$$ Test, at the \(10 \%\) significance level, whether the population mean of \(X\) is less than 7.5.

Question 7:
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(H_0: \mu = 7.5\), \(H_1: \mu < 7.5\)B1 State hypotheses (A.E.F.)
\(\bar{x} = 70.4/10 = 7.04\)M1 Calculate sample mean
\(s^2 = 8.48/9 = 211/225\) or \(0.9422\) or \(0.9707^2\)M1 Estimate population variance (allow biased: \(0.848\) or \(0.9209^2\))
\(t = (\bar{x} - 7.5)/(s/\sqrt{10}) = \pm 1.49_{[9]}\)M1 *A1 Calculate value of \(t\) (to 3 s.f.)
\(t_{9,\,0.9} = 1.38_{[3]}\)*B1 State or use correct tabular \(t\) value (or compare \(\bar{x}\) with \(7.5 - 0.425 = 7.07_{[5]}\))
Mean is less than \(7.5\)B1 Correct conclusion (AEF, dep *A1, *B1)
Total: 7 marks
## Question 7:

| Answer/Working | Marks | Guidance |
|---|---|---|
| $H_0: \mu = 7.5$, $H_1: \mu < 7.5$ | B1 | State hypotheses (A.E.F.) |
| $\bar{x} = 70.4/10 = 7.04$ | M1 | Calculate sample mean |
| $s^2 = 8.48/9 = 211/225$ or $0.9422$ or $0.9707^2$ | M1 | Estimate population variance (allow biased: $0.848$ or $0.9209^2$) |
| $t = (\bar{x} - 7.5)/(s/\sqrt{10}) = \pm 1.49_{[9]}$ | M1 *A1 | Calculate value of $t$ (to 3 s.f.) |
| $t_{9,\,0.9} = 1.38_{[3]}$ | *B1 | State or use correct tabular $t$ value (or compare $\bar{x}$ with $7.5 - 0.425 = 7.07_{[5]}$) |
| Mean is less than $7.5$ | B1 | Correct conclusion (AEF, dep *A1, *B1) |
| **Total: 7 marks** | | |

---
7 A random sample of 10 observations of a normally distributed random variable $X$ gave the following summarised data, where $\bar { x }$ denotes the sample mean.

$$\Sigma x = 70.4 \quad \Sigma ( x - \bar { x } ) ^ { 2 } = 8.48$$

Test, at the $10 \%$ significance level, whether the population mean of $X$ is less than 7.5.

\hfill \mbox{\textit{CAIE FP2 2013 Q7 [7]}}