CAIE FP2 2013 November — Question 9 11 marks

Exam BoardCAIE
ModuleFP2 (Further Pure Mathematics 2)
Year2013
SessionNovember
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicLinear regression
TypeRelate two regression lines
DifficultyStandard +0.3 This is a straightforward application of standard regression formulas: recognizing that r² equals the product of regression slopes, using the t-test for correlation with given critical values, finding means from the intersection of regression lines, and making a prediction. All steps are routine recall of A-level statistics techniques with no novel problem-solving required, though it does test understanding of the relationship between the two regression lines.
Spec5.08a Pearson correlation: calculate pmcc5.08d Hypothesis test: Pearson correlation5.09a Dependent/independent variables5.09c Calculate regression line

9 For a random sample of 10 observations of pairs of values \(( x , y )\), the equations of the regression lines of \(y\) on \(x\) and of \(x\) on \(y\) are $$y = 4.21 x - 0.862 \quad \text { and } \quad x = 0.043 y + 6.36$$ respectively.
  1. Find the value of the product moment correlation coefficient for the sample.
  2. Test, at the \(10 \%\) significance level, whether there is evidence of non-zero correlation between the variables.
  3. Find the mean values of \(x\) and \(y\) for this sample.
  4. Estimate the value of \(x\) when \(y = 2.3\) and comment on the reliability of your answer.

Question 9(i):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(r^2 = 4.21 \times 0.043 = 0.181\) or \(0.425^2\)M1 A1 Find sample coefficient using \(r^2 = b_1 b_2\)
\(r = 0.425\)*A1
Subtotal: 3 marks
Question 9(ii):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(H_0: \rho = 0\), \(H_1: \rho \neq 0\)B1 State both hypotheses
\(r_{10,\,5\%} = 0.549\)*B1 State or use correct tabular one-tail \(r\) value
Accept \(H_0\) if \(r <\) tabular value
There is no non-zero correlationA1 Correct conclusion (AEF, dep *A1, *B1)
Subtotal: 4 marks
Question 9(iii):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(\bar{x} = 7.72\) and \(\bar{y} = 31.6\)M1 A1 Solve regression eqns for mean values
Subtotal: 2 marks
Question 9(iv):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(x = 6.46\) or \(0.751\)B1 Estimate \(x\) from either eqn.
Not reliable because e.g. value of \(r\) is small, or range of data is unknown, or two estimates of \(x\) very differentB1 State valid comment on reliability
Subtotal: 2 marks
Total: 11 marks
## Question 9(i):

| Answer/Working | Marks | Guidance |
|---|---|---|
| $r^2 = 4.21 \times 0.043 = 0.181$ or $0.425^2$ | M1 A1 | Find sample coefficient using $r^2 = b_1 b_2$ |
| $r = 0.425$ | *A1 | |
| **Subtotal: 3 marks** | | |

## Question 9(ii):

| Answer/Working | Marks | Guidance |
|---|---|---|
| $H_0: \rho = 0$, $H_1: \rho \neq 0$ | B1 | State both hypotheses |
| $r_{10,\,5\%} = 0.549$ | *B1 | State or use correct tabular one-tail $r$ value |
| Accept $H_0$ if $|r| <$ tabular value | M1 | Valid method for reaching conclusion |
| There is no non-zero correlation | A1 | Correct conclusion (AEF, dep *A1, *B1) |
| **Subtotal: 4 marks** | | |

## Question 9(iii):

| Answer/Working | Marks | Guidance |
|---|---|---|
| $\bar{x} = 7.72$ and $\bar{y} = 31.6$ | M1 A1 | Solve regression eqns for mean values |
| **Subtotal: 2 marks** | | |

## Question 9(iv):

| Answer/Working | Marks | Guidance |
|---|---|---|
| $x = 6.46$ or $0.751$ | B1 | Estimate $x$ from either eqn. |
| Not reliable because e.g. value of $r$ is small, or range of data is unknown, or two estimates of $x$ very different | B1 | State valid comment on reliability |
| **Subtotal: 2 marks** | | |
| **Total: 11 marks** | | |

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9 For a random sample of 10 observations of pairs of values $( x , y )$, the equations of the regression lines of $y$ on $x$ and of $x$ on $y$ are

$$y = 4.21 x - 0.862 \quad \text { and } \quad x = 0.043 y + 6.36$$

respectively.\\
(i) Find the value of the product moment correlation coefficient for the sample.\\
(ii) Test, at the $10 \%$ significance level, whether there is evidence of non-zero correlation between the variables.\\
(iii) Find the mean values of $x$ and $y$ for this sample.\\
(iv) Estimate the value of $x$ when $y = 2.3$ and comment on the reliability of your answer.

\hfill \mbox{\textit{CAIE FP2 2013 Q9 [11]}}