Challenging +1.2 This is a standard moment of inertia calculation requiring application of the parallel axis theorem to multiple components (three rods in different orientations plus a disc). While it involves several steps and careful bookkeeping of distances, the techniques are routine for Further Maths students who have studied this topic. The setup is clearly defined with no geometric ambiguity, making it a straightforward but moderately lengthy calculation.
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Three identical uniform rods, \(A B , B C\) and \(C D\), each of mass \(M\) and length \(2 a\), are rigidly joined to form three sides of a square. A uniform circular disc, of mass \(\frac { 2 } { 3 } M\) and radius \(a\), has the opposite ends of one of its diameters attached to \(A\) and \(D\) respectively. The disc and the rods all lie in the same plane (see diagram). Find the moment of inertia of the system about the axis \(A D\).
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\includegraphics[max width=\textwidth, alt={}, center]{b486decd-75b8-44bd-889f-2472f1163871-2_553_435_258_854}
Three identical uniform rods, $A B , B C$ and $C D$, each of mass $M$ and length $2 a$, are rigidly joined to form three sides of a square. A uniform circular disc, of mass $\frac { 2 } { 3 } M$ and radius $a$, has the opposite ends of one of its diameters attached to $A$ and $D$ respectively. The disc and the rods all lie in the same plane (see diagram). Find the moment of inertia of the system about the axis $A D$.
\hfill \mbox{\textit{CAIE FP2 2013 Q1 [6]}}