CAIE FP1 2002 November — Question 3 6 marks

Exam BoardCAIE
ModuleFP1 (Further Pure Mathematics 1)
Year2002
SessionNovember
Marks6
PaperDownload PDF ↗
TopicProof by induction
TypeProve sequence property via recurrence
DifficultyStandard +0.8 This is a two-stage induction problem requiring algebraic manipulation of the recurrence relation before proving divisibility. Students must simplify a_{n+1} - a_{n} to find a useful recurrence, then apply induction with modular arithmetic. The combination of establishing the recurrence and proving divisibility by 24 elevates this above standard single-step induction proofs, but it remains a structured Further Maths exercise with clear guidance.
Spec4.01a Mathematical induction: construct proofs8.02e Finite (modular) arithmetic: integers modulo n

3 It is given that, for \(n = 0,1,2,3 , \ldots\), $$a _ { n } = 17 ^ { 2 n } + 3 ( 9 ) ^ { n } + 20$$ Simplify \(a _ { n + 1 } - a _ { n }\), and hence prove by induction that \(a _ { n }\) is divisible by 24 for all \(n \geqslant 0\).

3 It is given that, for $n = 0,1,2,3 , \ldots$,

$$a _ { n } = 17 ^ { 2 n } + 3 ( 9 ) ^ { n } + 20$$

Simplify $a _ { n + 1 } - a _ { n }$, and hence prove by induction that $a _ { n }$ is divisible by 24 for all $n \geqslant 0$.

\hfill \mbox{\textit{CAIE FP1 2002 Q3 [6]}}